When the forces acting on a particle are resolved into cylindrical components, friction forces always act in the
1 answer:
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Answer:
- 59.97 º at 18.23 mph
Explanation:
To find Sammy's course you have to add the two velocities (vectors), 18 mph 327º and 4 mph 60º.
To add the two vectors analytically you decompose each vector into their vertical and horizontal components.
<u>1. 18 mph 327º</u>
- Horizontal component: 18 mph × cos (327º) = 15.10 mph
- Vertical component: 18 mph × sin (327º) = - 9.80 mph
- Vector notation:
<u>2. 4 mph 60º</u>
- Horizontal component: 4 mph × cos (60º) = 2.00 mph
- Vertical component: 4 mph × sin (60º) = 3.46 mph
- Vector notation:
<u>3. Addition:</u>
You add the corresponding components:
To find the magnitude use Pythagorean theorem:
<u>4. Direction:</u>
Use the tangent ratio:
Find the inverse:
- arctan (1.73) ≈ 59.97º
For this case, what we must do is to rewrite these measurements in the same unit in order to compare them.
By writing the measurements in meters we have:
Therefore, physically the correct measure is:
Answer:
the length of a student's textbook most likely is:
30 centimeters