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Nutka1998 [239]
2 years ago
5

Skydiver jumps out of a plane she falls down word and very fast P. When she Open Sarah parachute she slows down. What force pull

s the skydiver to the ground?
Physics
1 answer:
Thepotemich [5.8K]2 years ago
4 0
There are two forces acting on a parachute with a parachutist: the force of gravity and the air resistance. The force pulling the skydiver to the ground would be Wright force
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Answer:

7772.72N

Explanation:

When u draw your FBD, you realize you have 3 forces (ignore the force the car produces), gravity, normal force and static friction. You also realize that gravity and normal force are in our out of the page  (drawn with a frame of reference above the car). So that leaves you with static friction in the centripetal direction.

Now which direction is the static friction, assume that it is pointing inward so

Fc=Fs=mv²/r=1900*15²/55=427500/55=7772.72N

Since the car is not skidding we do not have kinetic friction so there can only be static friction. One reason we do not use μFn is because that is the formula for maximum static friction, and the problem does not state there is maximum static friction.

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3 years ago
A wave is 8 meters long and has a frequency of 3 Hz. Find speed
Olenka [21]

Answer:

The speed is 24 \frac{meter}{s}

Explanation:

A wave is a disturbance that propagates through a certain medium or in a vacuum, with transport of energy but without transport of matter.

The wavelength is the minimum distance between two successive points of the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The speed of propagation is the speed with which the wave propagates in the middle, that is, the magnitude that measures the speed at which the wave disturbance propagates along its displacement. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation:

v = f * λ.

In this case, λ= 8 meter and f= 3 Hz

Then:

v= 3 Hz* 8 meter

So:

v= 24 \frac{meter}{s}

<u><em>The speed is 24 </em></u>\frac{meter}{s}<u><em></em></u>

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Because of barriers and obstructions, you can see only a tiny fraction of a standing wave on a string. You do not know, for inst
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(1) Sure, the frequency is 1000 Hz.

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Frequency = wave speed ÷ wave distance

wave speed = 100 m/s

wave distance = 10 cm = 10/100 = 0.1 m

Frequency = 100 ÷ 0.1 = 1000 Hz

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