Assuming conditions are at 25c and 1 bar 101.25 Kpa 1 mole of gas is equal to 22.4 L
So if you have 500L of ar gas the you have : 500L / 22.4 × 1 Mole = 22.3 moles of ar after accounting for sig figs..Hope that helps
Answer:
530.835 g
Explanation:
First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:
- 244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid
Theoretically,<em> one mol of ethyl benzene would produce one mol of benzoic acid</em>. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.
With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:
- 2.00 moles benzoic acid *
= 5.00 moles ethyl benzene
Finally we <u>convert moles of ethyl benzene </u>(C₈H₁₀)<u> into grams</u>, using its <em>molar mass</em>:
- 5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene
Answer:
CH3CHO+H2O → CH3OCH3 - addition
CH,CICH CI + Zn → C2H4 + ZnCl2 - elimination
CH3CH3Br + OH – CH3CH3OH + Br - substitution
2CH2COOH >>(CH3CO)20 + H20 - condensation
Explanation:
An addition reaction is a reaction in which a specie is added across the double bond as we can see in CH3CHO+H2O → CH3OCH3.
In an elimination reaction, a small molecule is lost from a saturated compound to form the corresponding unsaturated compound as in CH,CICH CI + Zn → C2H4 + ZnCl2
In a substitution reaction, a chemical moiety replaces another in a molecule as in; CH3CH3Br + OH – CH3CH3OH + Br .
A condensation reaction is in which two molecules are joined together to form a bigger molecule as in; 2CH2COOH >>(CH3CO)20 + H20.
Explanation:
Given problem:
Find the molar mass of:
SO₃ and C₁₀H₈
Solution:
The molar mass of a compound is the mass in grams of one mole of the substance.
To solve this, we are going to add the individual atomic masses of the elements in the compound;
Atomic mass;
S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol
For SO₃;
= 32 + 3(16)
= 32 + 48
= 80g/mol
For C₁₀H₈
= 10(12) + 8(1)
= 120 + 8
= 128g/mol
<h3>Answer:</h3>
Phosphoric acid reacts with magnesium hydroxide to produce magnesium phosphate and water via the following reaction:
2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O
(solid) (solid) (solid) (liquid)
<h3>Explaination:</h3>
This is a typical neutralization reaction of an acid with a base to form a salt and water. The reaction is exothermic, gives off heat,
ΔH < 0 , and may be balanced by adding balancing numbers in front, ie adding molecules, in order to ensure that the total number of atoms of each element is the same on the left and right hand sides of the equation.
Doing so we obtain :
2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O
(solid) (solid) (solid) (liquid)
<h3>hope it helps :)</h3>
