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baherus [9]
2 years ago
13

Which is associated with low humidity? *

Chemistry
2 answers:
Natalka [10]2 years ago
5 0

Answer:

guy above me is right

Explanation:

100% on quiz

mel-nik [20]2 years ago
4 0

Answer:

A: dry air

Explanation:

Trust me this is right, I’m doing the exam rn and if its not right I will come back and edit this.

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A liquid is placed in an evacuated, sealed flask. When will this closed system reach dynamic equilibrium?
timurjin [86]
The liquid will stop converting into vapor. This process is to balanced the amount of substance of both phases inside the flask. 
4 0
3 years ago
Read 2 more answers
A 44.0 g sample of an unknown metal at 99.0 oC was placed in a constant-pressure calorimeter of negligible heat capacity contain
tatiyna

Answer:

C_m=0.474\frac{J}{g\°C}

Explanation:

Hello.

In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:

Q_m=-Q_w

Thus, in terms of masses, specific heats and temperatures we can write:

m_mC_m(T_{eq}-T_m)=-m_wC_w(T_{eq}-T_w)

Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:

C_m=\frac{-m_wC_w(T_{eq}-T_w)}{m_m(T_{eq}-T_m)}

Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:

C_m=\frac{-80.0g*4.184\frac{J}{g\°C} (28.4\°C-24.0\°C)}{44.0g(28.4\°C-99.0\°C)}\\\\C_m=0.474\frac{J}{g\°C}

Best regards!

6 0
3 years ago
The normal boiling point of bromine is 58.8°C, and its enthalpy of vaporization is 30.91 kJ/mol. What is the approximate vapor p
saul85 [17]

Answer : The vapor pressure of bromine at 10.0^oC is 0.1448 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of bromine at 10.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 10.0^oC=273+10.0=283.0K

T_2 = normal boiling point of bromine = 58.8^oC=273+58.8=331.8K

\Delta H_{vap} = heat of vaporization = 30.91 kJ/mole = 30910 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{30910J/mole}{8.314J/K.mole}\times (\frac{1}{283.0K}-\frac{1}{331.8K})

P_1=0.1448atm

Hence, the vapor pressure of bromine at 10.0^oC is 0.1448 atm.

4 0
3 years ago
Which is a change or signal in the environment that can make an organism
nadya68 [22]

Answer:

I'm pretty sure its stimulus

7 0
3 years ago
A chemical reaction takes place in which energy is absorbed arrange the characteristics of the reaction in order from start to f
Nostrana [21]
<span>A chemical reaction in which energy is absorbed is known as an endothermic reaction. The characteristics of the reaction in order from start to finish is as follows:

1. Lower energy of reactants
2. Transition state
3. Higher energy of products

This implies that in an endothermic reaction, </span><span>the products are less stable than the reactants.</span>
5 0
3 years ago
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