Answer:
The mass we will get from AgCl is 0.839g
Explanation:
Hello!
Let's solve this!
The reaction is:
2AgC2H3O2 + MgCl2 ---> 2AgCl + Mg (C2H3O2) 2
The data we have are:
V1 = 75mL * (1L / 1000L) = 0.075L
M1 = 0.078M
V2 = 55mL * (1L / 1000mL) = 0.055L
M2 = 0.109M
The molarity formula is
M = mol / V
We calculate the moles of each compound:
molAgC2H3O2 = 0.075L * 0.078mol / L = 0.00585mol
molMgCl = 0.055L * 0.109M = 0.005995
We calculate the compound that is in excess, and then use the limiting reagent to calculate the amount of product we will obtain.
Since there are two Cl in MgCl2, this means that we have 0.01199 mol to produce the product, but we will only use 0.00585 mol which is the amount we have of AgC2H3O2. So MgCl is the excess reagent.
Then:
AgCl mass = 0.00585mol * (2mol AgCl / 2molAgC2H3O2) * (143.34g AgCl / 1mo AgCl) = 0.839gAgCl
The mass we will get from AgCl is 0.839g
The volume occupied by the given mol of helium gas at the given temperature and pressure is 91.6L.
The Ideal gas Law, also called the overall fuel equation, is the equation of kingdom of a hypothetical ideal gas. It is a superb approximation of the conduct of many gases below many situations, even though it has several limitations.
The precise gas regulation states that PV = NRT, wherein P is absolutely the pressure of a gasoline,volume V is the quantity it occupies, N is the quantity of atoms and molecules inside the fuel, and T is its absolute temperature.
Given;
Amount of helium n = 2.59 mole
Pressure p = 0.826 atm
Temperature T = 356 K
The volume of Helium = ?
PV = nRT
V = nRT/P
V = 2.59 mole * 0.826 atm * 356K/0.826
V = 75.6626/0.826
V = 91.6 L
Learn more about volume here:-brainly.com/question/463363
#SPJ4
D is the correct answer for your question. Maybe I am not sure.
Answer:
it may be electron, atom or ions depend on the nature of the substance and the character of reaction
like :- particles per mole, coulombs per electron