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Dmitry [639]
4 years ago
9

A student drops a 95g object into a graduated cylindor that has 30ml of water in it. After the object is added to the cylinder t

he water level reads 63ml. What is the density of the object? ​
Chemistry
1 answer:
Mnenie [13.5K]4 years ago
8 0

Answer:

<h3>The answer is 2.88 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 95g

volume = final volume of water - initial volume of water

volume = 63 - 30 = 33 mL

We have

density =  \frac{95}{33}  \\  = 2.87878787...

We have the final answer as

<h3>2.88 g/mL</h3>

Hope this helps you

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using the equation you wrote determine how many moles of butane c4h10 are needed to react with 5.5 moles of oxygen
GaryK [48]

Answer:

0.846 moles.

Explanation:

  • This is a stichiometric problem.
  • The balanced equation of complete combustion of butane is:

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

  • It is clear from the stichiometry of the balanced equation that complete combustion of 1.0 mole of butane needs 6.5 moles of O₂ to produce 4 moles of CO₂ and 5 moles of H₂O.

<u><em>Using cross multiplication:</em></u>

  • 1.0 mole of C₄H₁₀ reacts with → 6.5 moles of O₂
  • ??? moles of C₄H₁₀ are needed to react with → 5.5 moles of O₂
  • The number of moles of C₄H₁₀ that are needed to react with 5.5 moles of O₂ = (1.0 x 5.5 moles of O₂) / (6.5 moles of O₂) = 0.846 moles.
3 0
3 years ago
For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


7 0
4 years ago
Read 2 more answers
How many grams of water are produced from 100 grams of oxygen?
Allisa [31]

Answer:

28,125 g

Explanation:

m(O₂) = 100 g

n(O₂) =M(O₂)/m(O₂)=32 gram per mole / 100 g = 0,32 mole

O₂ + 2H₂ ⇒ 2H₂O  ,  n(H₂O) = 2 × n(O₂)

m(H₂O) = M(H₂O)/2 × n(O₂) = 18 grams per mole / 2 × 0,32 mole = 28,125 g

6 0
3 years ago
What formula results when Ca+2 and Br -1 ions bond?
olga nikolaevna [1]
CaBr2
Because of the criss cross method of switching the charges
3 0
3 years ago
Why does a tree cast a shadow during the daytime? A. The tree is a source of light for the Earth. B. The tree creates sunlight.
Minchanka [31]
The answer is C because uh. It makes sense
8 0
3 years ago
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