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shtirl [24]
3 years ago
13

1) According to the law of conservation of energy, A) an object loses most of its energy as friction. B) the total amount of ene

rgy for a system stays the same. C) the potential energy of an object is always greater than its kinetic energy. D) the kinetic energy of an object is always greater than its potential energy.
Physics
1 answer:
Blababa [14]3 years ago
5 0
Your answer is C) <span> the potential energy of an object is always greater than its kinetic energy </span>
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A net force of -1,000 Newtons is delivered to the object over a time of .02 seconds. Calculate the new velocity of the object.
MariettaO [177]
The change in velocity (v₂ - v₁) is

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Call it a crazy hunch, but I can't shake the feeling that there was more
to the question before the part you copied, that mentioned the object's
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A 3.1-kilogram gun initially at rest is free to
34kurt
The conservation of momentum states that the total momentum in a system is constant if there is no external force acting on the system. The total momentum in the gun bullet system is 0 so it must stay that way.

The momentum of the bullet is mv = 0.015*500=7.5
The momentum of the gun must be the same to keep the total momentum of the system equal to zero, so we know that p = 7.5 for the gun.
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8 0
3 years ago
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In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 36.0mi/gal , how many liters of gasoline would
Zigmanuir [339]
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3 0
3 years ago
Which of the following describes what all electromagnetic waves have in common?
Solnce55 [7]
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3 0
2 years ago
Two equally charged tiny spheres of mass 1.0 g are placed 2.0 cm apart. When released, they begin to accelerate away from each o
zhannawk [14.2K]

Answer:

The magnitude of the charge on each sphere is 0.135 μC

Explanation:

Given that,

Mass = 1.0

Distance = 2.0 cm

Acceleration = 414 m/s²

We need to calculate the magnitude of charge

Using newton's second law

F= ma

a=\dfrac{F}{m}

Put the value of F

a=\dfrac{kq^2}{mr^2}

Put the value into the formula

414=\dfrac{9\times10^{9}\times q^2}{1.0\times10^{-3}\times(2.0\times10^{-2})^2}

q^2=\dfrac{414\times1.0\times10^{-3}\times(2.0\times10^{-2})^2}{9\times10^{9}}

q^2=1.84\times10^{-14}

q=0.135\times10^{-6}\ C

q=0.135\ \mu C

Hence, The magnitude of the charge on each sphere is 0.135μC.

7 0
3 years ago
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