Answer
given,
wavelength of laser light = 632.8 nm
assuming that aperture of lens be equal to dia = 1 mm
now,
When laser light passes through aperture diffraction of light takes place
The first diffraction minima occurs at
where a is the width of aperture
λ is the wavelength of light
p is the angle
p = 0.0363° angle of the first dark ring
Answer:
d' = 0.86 mm
Explanation:
First we need to find the area of low power field:
A = πd²/4
where,
A = Area = ?
d = diameter = 1.5 mm
Therefore, using the value of diameter, we get:
A = π(1.5 mm)²/4
A = 1.767 mm²
Now, the new object occupies 1/3rd of this area:
A' = (1/3)A
πd'²/4 = (1/3)A
d'² = (4/3π) A
d'² = (4/3π)(1.767 mm²)
d' = √(0.75 mm²)
<u>d' = 0.86 mm</u>
Answer:
The work done is 13.875 J.
Explanation:
Given that,
Mass of ball = 0.25 kg
Initial speed = 20 m/s
Final speed = 17 m/s
We need to calculate the work done
Using formula of work done
Work done by the friction
Negative sign shows the friction always against displacement.
Hence, The work done is 13.875 J.
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