Answer:
20+14
Step-by-step explanation:
Math
Answer:

Step-by-step explanation:
Answer:
C
Step-by-step explanation:
We can use the factored form of the quadratic equation, given by:

Where <em>a</em> is the leading coefficient and <em>p</em> and <em>q</em> are the zeros.
We have zeros <em>x</em> = -2 and <em>x</em> = 3. So, let <em>p</em> = -2 and <em>q</em> = 3:

Next, we are given that our <em>y-</em>intercept is (0, -30).
In other words, when <em>x</em> = 0, <em>y</em> = -30. So:

Solve for <em>a:</em>
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Hence, our factored equation is:

For the standard form, expand:

Simplify:

Distribute:

Our answer is C.
<span>You need to find the least common multiple of 6 and 3. This the minimum whole number that contains the number of boxes in one package of pasta and the number of jars in one package of sauce. t he least common multiple of 6 and 3 is 6. This means that Manny can make 6 dinners, which will be made with 1 package of pasta (6 boxes ) and two packages of sauce (2 * 3 = 6 jars).</span>