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2 years ago

An elevator has the mass of 3 tons of power needed to raise the elevator 50m in 15 s?

Physics

2 answers:

9966 [12]2 years ago

5 0

Answer:

Mass=3,time=15,height=50,g=10,Power=?.

Power=mgh/t.....3×10×15=1500/15=100Watts.

xxMikexx [17]2 years ago

4 0

Answer:

$\huge \boxed{\mathrm{100 \ Watts}}$

Explanation:

$\sf \displaystyle P=\frac{mgh }{t} \\\\\\ P=power \ (W) \\\\ m=mass \ (kg) \\\\ g=gravity \ acceleration \ (m/s^2) \\\\ h=height \ (m) \\\\ t=time \ taken \ (s)$

$\sf \displaystyle P=\frac{3 \times 10 \times 50 }{15}$

$\sf \displaystyle P=\frac{1500 }{15}$

$\sf \displaystyle P=100$

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A 500 N force accelerates an object at 20 m s-2. What is its mass?

avanturin [10]

Answer: The mass of the object is 25kg.

The given question deals with Newton's second law of motion and its applications.

Explanation: Given force, F=500N

acceleration, a=20 m/ $s^{2}$

From Newton's 2nd law of motion , we have

F=ma where m=mass of the object

⇒500=m×20

⇒m=500/20=25

∴ Mass of the object is 25 kg .

Reference Link: brainly.com/question/1141170

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1 year ago

A 50 kg runner runs up a flight of stairs. The runner starts out covering 3 steps every second. At the end the runner stops. Thi

nadezda [96]

To solve the problem it is necessary to take into account the concepts of kinematic equations of motion and the work done by a body.

In the case of work, we know that it is defined by,

$W = F * d$

Where,

F= Force

d = Distance

The distance in this case is a composition between number of steps and the height. Then,

$d=h*N$ , for h as the height of each step and N number of steps.

On the other hand we have the speed changes, depending on the displacement and acceleration (omitting time)

$V_f^2-V_i^2 = 2a\Delta X$

Where,

$V_f =$ Final velocity

$V_i =$ Initial Velocity

a = Acceleration

$\Delta X =$ Displacement

PART A) For the particular case of work we know then that,

$W = F*d$

$W = m*g*(h*N)$

$W = 50*9.8*(0.3*30)$

$W = 4.41kJ$

Therefore the Work to do that activity is 4.41kJ

PART B) To find the acceleration (from which we can later find the time) we start from the previously given equation,

$V_f^2-V_i^2 = 2a\Delta X$

Here,

$V_i = \frac{0.3*3}{1} = 0.90m/s\rightarrow$ 3 steps in one second

$v_f = 0$

Replacing,

$V_f^2-V_i^2 = 2a\Delta X$

$0-0.9^2=2a(30*0.3)$

Re-arrange for a,

$a = -\frac{0.9^2}{2*30*0.3}$

$a = -45*10^{-3}m/s^2$

At this point we can calculate the time, which is,

$t = \frac{\Delta V}{a}$

$t = \frac{0-0.9}{-45*10^{-3}}$

$t = 20s$

With time and work we can finally calculate the power

P = \frac{W}{t} = \frac{4.41}{20}

P = 0.2205kW

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3 years ago

How much force does it take to bring a 1,375 N car from rest to a velocity of 26 m/s in 6 seconds?

V125BC [204]

Explanation:

Mass of car = 137.5 kg

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3 years ago

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Lostsunrise [7]

The answer should be B, Condense.

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3 years ago

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