You should draw a free body diagram, or a diagram of sorts. It’s always helpful to do so when solving physics questions.
Givens:
Acceleration (a) = 32.17 ft/s² as that is the only force acting on the stone in free fall assuming no air resistance
Initial velocity (V1) = 0 ft/s as that it the starting speed of the stone as all objects about to move from rest must start at 0 velocity at rest = 0 velocity
Final velocity (V2) = 120 ft/s
Displacement aka. the
height of the cliff (Δd) = ? ft
The kinematic formula we can use is: V2² = V1² + 2(a)(Δd)
Isolate to solve for Δd and just plug in the numbers!
V2² = V1² + 2(a)(Δd)
(120)² = (0)² + 2(32.17)(Δd)
14400 = 2(32.17)(Δd)
= Δd
223.9 = Δd
Therefore, the height of the cliff is 223.9 ft! Hope this helped! :)
Answer:
Part a)
Part b)
Explanation:
As we know that electric force on electric charge is given as
here we have
E = 153 N/C
now force is given as
Gravitational force on electric charge near surface of earth is given as
now the ratio of two forces is given as
Part b)
Now the ball is balanced by the electric force and the force of gravity on it
so here we have
here we have