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xz_007 [3.2K]
3 years ago
13

Two forces are applied to a 2.0 kg block on a frictionless horizontal surface. F1 = 8.ON is applied to the left while F2 = 3.0 N

is applied to the right. What is the
acceleration of the block?


A.) 2.5 m/s^2 to the left

B.) 1.5 m/s^2 to the right

C.) 4.0 m/s^2 to the left

D.) 2.5 m/s^2 to the right
Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

It is C 5.0 m/s 2 to the right

Explanation:

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Answer:

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Recall that \omega=\frac{2\pi}{T}\\, that is the distance traveled in one revolution divided into the time of one revolution. Replacing and solving for k:

k=\frac{m4\pi^2}{T^2}\\k=\frac{(0.326kg)4\pi^2}{(0.25s)^2}\\k=205.92\frac{N}{m}

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v_{max}=A\omega\\A=\frac{v_{max}}{\omega}\\A=\frac{(v_{max})T}{2\pi}\\A=\frac{(5.98\frac{m}{s})0.25s}{2\pi}\\A=0.24m

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___________________________________________

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