3 years ago

How would decreasing the time it takes you to run a certain distance affect your speed?

1 answer:

5 0

You have it exactly backwards.

IN ORDER TO run a certain distance in less time,
you must increase your speed. That's the only way.

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A charging RC circuit controls the intermittent windshield wipers in a car. The emf is 12.0 V. The wipers are triggered when the

lilavasa [31]

Answer:

$R=803k\Omega$

Explanation:

We have the following information,

$V_0 = 12V\\V=10V\\c= 1.25*10^{-6}F\\t=1.8s$

We apply the equation for capacitor charging the voltage across it,

$V=V_0 (1-e^{-t/x})\\e^{-t/x}=1-(\frac{V}{V_0})\\-\frac{t}{Rc}=ln(\frac{V}{V_0})\\R=-\frac{t}{ln(\frac{V}{V_0})*c}$

Replacing values,

$R=-\frac{1.8}{ln(10/12)*1.25*10^{-6}}$

$R=803k\Omega$

3 0

2 years ago

Momentum usually has the symbol p It is a vector, What is the correct way to

Nadya [2.5K]

Answer:

Add an arrow above the symbol p to show it is a vector. Sometimes it is italicized in textbooks.

Explanation:

6 0

2 years ago

How much heat is needed to raise the temperature of a 100.0g of water by 85.0 c?

KatRina [158]

Answer:

35.7kJ

Explanation:

we can calculate the amount of heat energy required , using this formula

Q = mcθ

where.

Q = heat energy (Joules, J)

m = mass of a substance (kg)

c = specific heat capacity (units $Jkg^{-1} C^{-1}$ )

θ = change in temperature (Celcius,C or Kelvin K)

Assume Specific heat capacity (c) of water = $4200Jkg^{-1} C^{-1}$

mass =0.1 kg

$Q=0.1 kg*4200Jkg^{-1} C^{-1}*85C\\=35700J\\=35.7kJ$

3 0

2 years ago

Starting from rest, a crate of mass m is pushed up a frictionless slope of angle theta by a horizontal force of magnitude F. Use

ludmilkaskok [199]

Answer:

v = sqrt[2*(F*h*cot(theta)-mgh)/m]

Explanation:

Work = KE + Ug

F*r=1/2mv^2+mgh

1/2mv^2=F*r-mgh

v=sqrt[2(F*r-mgh)/m]

r=h/tan(theta)=h*cot(theta)

6 0

3 years ago

Based on the diagram of the two electrical circuits, assuming the lightbulbs are all identical, which circuit will draw more pow

pochemuha

In series connection in orde to find the total resistance we add all the resistance capacity but in parallel, we take the 1/R and resistance = V hence the series connection takes up more power,

8 0

3 years ago