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3 years ago

50 points!! Brainliest if correct!!

1 answer:

4 0

The answer is C. The answer is C because if u increase the surface area, the more reactants u will get. and if u get more The reactants will move faster. Hoped that Helped!:-)

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lana [24]

Answer:

To calculate the theoretical yield, determine the number of moles of each reactant, in this case the sole reactant ethanol. Convert the 100 g to moles; the molecular weight of ethanol is 46 g/mole, therefore: Since there is only one reactant, it is also the limiting reagent.

Explanation:

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4 0

3 years ago

If the volume of 1.00 mole of gas is tripled, what will happen to the pressure, if the temperature remains constant

Julli [10]

Answer:

The new pressure becomes one third of the initial pressure.

Explanation:

The relation between pressure and volume at constant temperature is given by :

$P\propto \dfrac{1}{V}\\\\P=\dfrac{1}{V}$

Let new pressure and volume be P' and V' respectively.

V'=3V (given)

So,

$P'=\dfrac{1}{V'}\\\\=\dfrac{1}{3V}\\\\=\dfrac{1}{3}\times \dfrac{1}{V}\\\\P'=\dfrac{1}{3}\times P$

Hence, new pressure becomes one third of the initial pressure.

8 0

3 years ago

Who is good at chemistry and wanna help me on my test Someone please

Alborosie

I’m ok at chemistry i can try to help

4 0

3 years ago

What minimum mass of iron (II) nitrate must be added to 10.0 of a 0.0699 M phosphate solution in order to completely precipitate

ad-work [718]

Answer: The minimum mass of iron (II) nitrate that must be added is 0.188 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of phosphate solution = 0.0699 M

Volume of solution = 10 mL = 0.010 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.0699M=\frac{\text{Moles of phosphate solution}}{0.010L}\\\\\text{Moles of phosphate solution}=(0.0699mol/L\times 0.010L)=6.99\times 10^{-4}mol$

The given chemical equation follows:

$2PO_4^{3-}(aq.)+3Fe(NO_3)_2(aq.)\rightarrow Fe_3(PO_4)_2(s)+6NO_3^-(aq.)$

By Stoichiometry of the reaction:

2 moles of phosphate solution reacts with 3 moles of iron (II) nitrate

So, $6.99\times 10^{-4}mol$ of phosphate solution will react with = $\frac{3}{2}\times 6.99\times 10^{-4}=1.049\times 10^{-3}mol$ of iron (II) nitrate

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of iron (II) nitrate = 180 g/mol

Moles of iron (II) nitrate = $1.049\times 10^{-3}$ moles

Putting values in above equation, we get:

$1.049\times 10^{-3}mol=\frac{\text{Mass of iron (II) nitrate}}{180g/mol}\\\\\text{Mass of iron (II) nitrate}=(1.049\times 10^{-3}mol\times 180g/mol)=0.188g$

Hence, the minimum mass of iron (II) nitrate that must be added is 0.188 grams

7 0

3 years ago

7. Which atomic particle has a neutral (0) charge?

Tasya [4]

Answer:

sodium

Explanation:

8 0

3 years ago