Answer:
grams of solution = 551.98 g
Explanation:
Given data:
Percentage of solution = 32.9
Mass of solute = 181.6 g
Grams of solvent = ?
Solution:
Formula:
% = [grams of solute / grams of solution] × 100
Now we will put the values in formula.
32.9 = [ 181.6 g / grams of solution] × 100
grams of solution = 181.6 g × 100 / 32.9
grams of solution = 18160 g /32.9
grams of solution = 551.98 g
JJ Thomson proved John Dalton's theory wrong, as Thomson discovered the electron. This showed that there were particles that were smaller than an atom, despite Dalton claiming that the atom is the smallest unit of matter.
The statement 'whether people should take medicine or if they should seek alternative treatments' describes an ethical dilemma that drug designers face.
<h3>What is drug development?</h3>
Drug development refers to all the processes from target drug identification to drug validation and commercialization.
Drug development involves different stages of development including preclinical and clinical trials.
Ethical dilemmas in drug development include the release of a drug that is ineffective when compared to parallel treatments.
Learn more about drug development here:
brainly.com/question/8187660
Answer : The rms speed of the molecules in a sample of 
gas at 300 K will be four times larger than the rms speed of 
molecules at the same temperature, and the ratio 
constant with increasing temperature.
Explanation :
Formula used for root mean square speed :
where,
= rms speed of the molecule
R = gas constant
T = temperature
M = molar mass of the gas
At constant temperature, the formula becomes,
And the formula for two gases will be,
Molar mass of = 32 g/mole
Molar mass of = 2 g/mole
Now put all the given values in the above formula, we get
Therefore, the rms speed of the molecules in a sample of gas at 300 K will be four times larger than the rms speed of molecules at the same temperature.
And the ratio constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.
