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4 years ago

Which change would cause the largest increase in a mountain climber’s gravitational potential energy?

Physics

2 answers:

3241004551 [841]4 years ago

5 0

<span>carrying twice the weight and climbing twice as high</span>

Andrew [12]4 years ago

5 0

Answer : The correct option is (c).

Explanation :

The energy which is due to the height of an object under the action of gravity is called gravitational potential energy.

Mathematically, it can be written as :

P = m g h

Where,

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object from the reference level

So, potential energy is directly proportional to both the mass and the height.

The statement about the largest increase in a mountain climber’s gravitational potential energy is "carrying twice the weight and climbing twice as high".

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A 2kg bowling ball rolls at a speed of 5 m/s on a roof of the building that is 40 meters tall. What is the kinetic energy

MrRa [10]

The kinetic energy is $\frac 1 2 m v^2$ and the height of the building doesn't matter at all.

$E = \frac 1 2 m v^2 = \frac 1 2 (2)(5)^2 = 25$ joules

8 0

3 years ago

A very light ping-pong ball moving east at a speed of 4 m/s collides with a very heavy stationary bowling ball. The Ping-Pong ba

KengaRu [80]

Answer:

They experience the same magnitude impulse

Explanation:

We have a ping-pong ball colliding with a stationary bowling ball. According to the law of conservation of momentum, we have that the total momentum before and after the collision must be conserved:

where is the initial momentum of the ping-poll ball

is the initial momentum of the bowling ball (which is zero, since the ball is stationary)

is the final momentum of the ping-poll ball

is the final momentum of the bowling ball

We can re-arrange the equation as follows or

which means (1) so the magnitude of the change in momentum of the ping-pong ball is equal to the magnitude of the change in momentum of the bowling ball.

However, we also know that the magnitude of the impulse on an object is equal to the change of momentum of the object:

(2) therefore, (1)+(2) tells us that the ping-pong ball and the bowling ball experiences the same magnitude impulse:

3 0

3 years ago

If the half-life of iodine-131 is 8.10 days, how long will it take a 50.00 g sample to decay to 6.25 g?

Sloan [31]

Answer:

your in mr langfords class

Explanation:

bruh moment

6 0

3 years ago

8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (

love history [14]

(1) acceleration, a = 4 m/ $s^{2}$ (2) acceleration of 10 N, $a_{1}$ = 1 m/ $s^{2}$ and acceleration of 30 N, $a_{2}$ = 3 m/ $s^{2}$

Explanation:

Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
Let $a_{1}$ be the acceleration for force 10 N, to find acceleration rearrange the equation to a = $\frac{F}{m}$ . When we substitute 10 N force and 10 kg mass of the box in the equation. We will get $a_{1}$ = 1 m/ $s^{2}$

Let $a_{2}$ be the acceleration for force 30 N, to find acceleration rearrange the equation to F = $\frac{F}{m}$ . When we substitute 30 N force and 10 kg mass of the box in the equation. We will get $a_{2}$ = 3 m/ $s^{2}$
To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/ $s^{2}$

3 0

3 years ago

What is the relationship between the force and the period in a mass hanging on a spring oscillation and why?

BabaBlast [244]

Explanation:

Period of a mass on a spring is:

T = 2π√(m/k)

T is a function of only m and k. So the period is independent of force.

5 0

3 years ago