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3 years ago

Which change would cause the largest increase in a mountain climber’s gravitational potential energy?

Physics

2 answers:

3241004551 [841]3 years ago

5 0

<span>carrying twice the weight and climbing twice as high</span>

Andrew [12]3 years ago

5 0

Answer : The correct option is (c).

Explanation :

The energy which is due to the height of an object under the action of gravity is called gravitational potential energy.

Mathematically, it can be written as :

P = m g h

Where,

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object from the reference level

So, potential energy is directly proportional to both the mass and the height.

The statement about the largest increase in a mountain climber’s gravitational potential energy is "carrying twice the weight and climbing twice as high".

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A cork is less dense

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2 years ago

A 0.325 g wire is stretched between two points 57.7 cm apart. The tension in the wire is 650 N. Find the frequency of first harm

Galina-37 [17]

Answer:

f = 931.1 Hz

Explanation:

Given,

Mass of the wire, m = 0.325 g

Length of the stretch, L = 57.7 cm = 0.577 m

Tension in the wire, T = 650 N

Frequency for the first harmonic = ?

we know,

$v =\sqrt{\dfrac{T}{\mu}}$

μ is the mass per unit length

μ = 0.325 x 10⁻³/ 0.577

μ = 0.563 x 10⁻³ Kg/m

now,

$v =\sqrt{\dfrac{650}{0.563\times 10^{-3}}}$

v = 1074.49 m/s

The wire is fixed at both ends. Nodes occur at fixed ends.

For First harmonic when there is a node at each end and the longest possible wavelength will have condition

λ=2 L

λ=2 x 0.577 = 1.154 m

we now,

v = f λ

$f = \dfrac{v}{\lambda}$

$f = \dfrac{1074.49}{1.154}$

f = 931.1 Hz

The frequency for first harmonic is equal to f = 931.1 Hz

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3 years ago

A horizontal force in used to pull a 5 kilogram cart at a constant speed of 5 meters per second across the floor as shown in the

ddd [48]

A cart is pulled by horizontal force such that it moves with constant velocity

So here since velocity is constant we can say that its acceleration will be ZERO

now here for zero acceleration we can say

$F_{net} = 0$

So here we will have

$F_{net} = F_{ap} - F_f = 0$

here we know that

$F_f = 10 N$

so we will have

$F_{ap} - 10 = 0$

$F_{ap} = 10 N$

so here applied force on handle will be

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2 years ago

How is a magnetable to pick up bits of metal without actually touching them?

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C.There is an invisible magnetic field around the magnet where it exerts magnetic force

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2 years ago

When a substance experiences a phase change (state of matter change) is this a chemical or physical change? How do you know?

makkiz [27]

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3 years ago