Check your work here:
1)7/8.
7/8=0.875 and 3/4=0.75
2)3/20.
3/20=0.15 and 12.5%=0.125
3)48.4
increase by 10% means you multiply 44 by 100%+10% or 110% to get 48.4
4)612
decrease by 10% means you multiply 680 by 100%-10% or 90% to get 612
5)36,36,60
132/(3+3+5)*3,132/(3+3+5)*3,132/(3+3+5)*5
6)9.6,22.4
32/10*3, 32/10*7
7)20
14/0.7
8)31.5
18/4*7
9)17/12
2/3=8/12, 3/4=9/12 8/12+9/12=17/12
10)15/4
5*3/4
11)8
2^2+2*2=4+4=8
12)0
(-2)^2+(-2)*2=4-4=0
13)3
3(x-3)=0,(x-3)=0,x=3
14)2/5 or 0.4
5x+1=3,5x=2,x=2/5
15)5n+2
The sequence difference is 5 and the first term is 7
16)20
6(3)+2=18+2=20
17)-5
4(-2)+3=-8+3=-5
18)1
the coefficient of x is 1
19)4pi or 12.56
area of a circle is r^2*pi=2^2*pi=4pi
20)14pi or 43.96
circumference of a circle=2r*pi=2*4*pi=14pi
Answer:
.
Step-by-step explanation:
A) f(x) = x-2 because the points in the y axis are -2 from the origin and x goes first
Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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the answer is B your welcome
