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34kurt
3 years ago
6

a roller coaster car rapidly picks up speed as it rolls down a slope. and it starts down the slope, its speed is 4 m/s. but 3 se

conds later, at the bottom of the slope, its speed is 22m/s what is the acceleration?
Physics
1 answer:
slamgirl [31]3 years ago
3 0

I hope this helps.

a=(V2-V1)/t

a=(22-4)/3

A=18/3

A=6m/s/s

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We will apply:
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4 years ago
Why do concave lenses always form virtual images?
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4 years ago
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Answer:

t = 5.48 × 10⁻³ s

Explanation:

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thus,

0.55\times \frac{\Delta V_{max}}{R}=\frac{\Delta V_{max}sin(2\pi \times 16.9\times t)}{R}

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I can only help you with the last two questions from lesson 5.01

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