1. An aqueous solution was prepared by mixing 70 g of an unknown nondissociating solute into 100 g of water. The solution has a
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Answer:
Lithium = 8%
Bromine = 92%
Explanation:
To calculate percent composition, you must:
- Calculate the molar mass.
- Divide the subtotal for each element's mass by the molar mass.
- Convert to a percentage
With that being said, given LiBr (Lithium Bromide), calculate the molar mass:
Lithium has an atomic weight of 7, and there is one Lithium atoms in LiBr. Bromine has an atomic weight of 80, and there is one Bromine atom in LiBr:
Add the two products:
The molar mass of LiBr is about 87 grams.
With that information, divide the subtotal of Lithium by the molar mass, and then multiply by 100 to convert to a percentage:
×
8.0459%
(Round to nearest percentage):
8%
Therefore, the percent composition of Lithium in the compound Lithium Bromide is about 8%.
Now, divide the subtotal of Bromine by the molar mass, and then multiply by 100 to convert to a percentage:
×
91.9540
(Round):
92%
Therefore, the percent composition of Bromine in the compound Lithium Bromide is about 92%.