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tangare [24]
3 years ago
13

If I place a pot of water over a fire (heat source), what will happen to the water?

Chemistry
1 answer:
seropon [69]3 years ago
6 0

Answer:

C. All of the water will get warm.

Explanation:

The water will get warm all together but slowly, eventually when it hits a certain high heated temperature it will start to boil.

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Nuclear fusion please help :/
fiasKO [112]

Answer:

  • The fuel for nuclear fusion is often uranium
  • Nuclear fusion is used to generate electricity at nuclear power plants

Explanation:

The most common nuclear fuel is made up of fissile elements such as Uranium, Neptunium, Plutonium,  Americium and  Curium, which are fissionable elements, which is when its nucleus is capable of undergoing a fission with neutrons free of any energy.

Nuclear fission can be used both for warlike purposes, as in the construction of atomic bombs, as well as for pacifist purposes, in the construction of reactors for the production of electrical energy.

4 0
3 years ago
How many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution
Natalija [7]
M=n/V , 4.5=n/1.5 , (45/10). (15/10)=n , (9/2).(3/2)=n=27/4 , n=6,75
3 0
3 years ago
a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the
butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}

Given ,  

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7  ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

T₂ = (28.1 + 273.15) K = 301.25 K  

Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0
3 years ago
12.2 scientific notation
Nadya [2.5K]

This would be 1.22 x 10^1

You simply move the decimal.

If this helped you, please list me as brainliest!

3 0
3 years ago
An electron moved from a higher energy level to a lower energy level. What most likely happened during the transition? (4 points
Alex787 [66]

Answer: The anwser is A a photon was realeased please mark brainliest

Explanation:

6 0
2 years ago
Read 2 more answers
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