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3 years ago

A variable that is manipulated by the scientist in order to answer a testable question is the _________

Chemistry

2 answers:

aliina [53]3 years ago

5 0

It is the independent variable

LiRa [457]3 years ago

3 0

Independent variable or manipulative variable. Different words same thing

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A patient taking _______ would have a history of mental depression.

ohaa [14]

The answer is Prozac

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3 years ago

ΔH for the formation of CuCl2 from its elements is -220.1 kJ/mol. How many kJ are associated with the formation of 0.30 mole of

otez555 [7]

0.3 * - 220.1 = - 66.03kJ

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3 years ago

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Trisha and her lab partner filled a beaker with 150 milliliters of a 0.10 M HCl solution. How many moles of HCl are in the beake

oksian1 [2.3K]

M=mol/liter
We know that we have 150ml=.15 L and .1 mol of HCl
Rearranging the molarity equation, we get
mol=M*l
mol=(.15)(.1)
=.015 mol

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3 years ago

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How many grams of water (H2O) are produced from 34 grams of oxygen (O2)? *

Dennis_Churaev [7]

Answer:

Explanation:

complete combustion reaction of ethane is given by the reaction

2C2H6+7O2..............4CO2+6H2O

no of moles in 34 grams of O2=34/32=1.063

7mole of O2 produced 6 moles of H2O

therefore 1.063 moles of O2 produced=1.063*6/7=0.9 moles

now 0.9 moles of H2O contain how much grams=0.9*18=16.2 grams

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2 years ago

How many moles of Carbon are in 3.06 g of Carbon

natta225 [31]

Answer:

$\boxed {\boxed {\sf 0.255 \ mol \ C }}$

Explanation:

If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

Look up the molar mass of carbon.

Carbon (C): 12.011 g/mol

Set up a ratio using the molar mass.

$\frac {12.011 \ g \ C}{ 1 \ mol \ C}$

Since we are converting 3.06 grams to moles, we multiply by that value.

$3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}$

Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.

$3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}$

$3.06 * \frac{1 \ mol \ C}{12.011 }$

$\frac {3.06}{12.011 } \ mol \ C$

$0.25476646 \ mol \ C$

The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

0.25476646

The 7 in the ten-thousandth place tells us to round the 4 up to a 5.

$0.255 \ mol \ C$

3.06 grams of carbon is approximately <u>0.255 moles of carbon.</u>

3 0

2 years ago