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The total heat of hydration of 1. 00 mol of gas phase ions and
ions is - 684 kJ/mol.
Calculation ,
Given data ,
Heat of solution = 17. 2 kJ/mol
lattice energy of KCl(s) = 701. 2 kJ/mol.
heat of hydration = ?
The KCl is formed by ions and
– ions
Δ = U° + Δ
Δ = Δ
- U° = 17. 2 kJ/mol - 701. 2 kJ/mol = - 684 kJ/mol
Hence, heat of hydration of 1. 00 mol of gas phase ions and
ions is - 684 kJ/mol.
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Answer:
A. Disturbing the equilibrium by adding NO2Cl decreases Qc to a value less than Kc.
B. To reach a new state of equilibrium, Qc therefore increases which means that the denominator of the expression for Qc decreases.
C. To accomplish this, the concentration of reagents decreases, and the concentration of products increases.
Explanation:
Hello,
In this case, for the equilibrium reaction:
Whose equilibrium expression is:
The proper matching is:
A. Disturbing the equilibrium by adding NO2Cl decreases Qc to a value less than Kc, since the denominator becomes greater, therefore, Qc decreases.
B. To reach a new state of equilibrium, Qc therefore increases which means that the denominator of the expression for Qc decreases, since the lower the denominator, the higher Qc as it has the concentration of reactants.
C. To accomplish this, the concentration of reagents decreases, and the concentration of products increases, since the reactants must be consumed in order to reestablish equilibrium by shifting the reaction towards the products.
Best regards.
Explanation:
The given reaction equation is as follows.
The value of = 59.1 kJ/mol
We know that ,
or,
= -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]
= -22.93
or,
=
Therefore,
=
=
Therefore, we can conclude that the value of in the intestinal tract is
.