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DerKrebs [107]
3 years ago
7

Calcium chloride is used to melt ice and snow on roads and sidewalks and to remove water from organic liquids. Calculate the mol

arity of a solution prepared by diluting 165 ml of 0.688 m calcium chloride to 925.0 ml.
Chemistry
1 answer:
Tomtit [17]3 years ago
5 0

Answer is: molarity of calcium chloride is 0.123 M.

V₁(CaCl₂) = 165 mL; initial volume of calcium chloride solution.

c₁(CaCl₂) = 0.688 M; initial concentration.

V₂(CaCl₂) = 925.0 mL; final volume.

c₂(CaCl₂) = ?; final concentration.

Use c₁V₁ = c₂V₂.

0.688 M · 165 mL = c₂(CaCl₂) · 925 mL.

c₂(CaCl₂) = (0.688 M · 165 mL) ÷ 925 mL.

c₂(CaCl₂) = 0.123 M.

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Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur
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Answer : The mass of water produced will be 32.78 grams.

Explanation : Given,

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First we have to calculate the moles of C_5H_{12}.

\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles

Now we have to calculate the moles of H_2O.

The balanced chemical reaction will be,

C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)

From the balanced reaction we conclude that

As, 1 mole of C_5H_{12} react to give 6 moles of H_2O

So, 0.3035 moles of C_5H_{12} react to give 0.3035\times 6=1.821 moles of H_2O

Now we have to calculate the mass of H_2O.

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g

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