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fomenos
3 years ago
9

How does the law of conservation of mass apply to this reaction C2H4+4O2-->4H2O+2CO2 .Only the oxygen needs to be balanced B.

The equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen and carbon C.The law of conservation of mass has already been applied D. Each element needs to be balanced
Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
6 0
C2H4+4O2-->4H2O+2CO2

the answer is C
Novosadov [1.4K]3 years ago
5 0
The answer would be c.
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What is the sum of the coefficients in the balanced chemical equation for the combustion of acetone, c3h6o(l), in air?
WITCHER [35]

The sum of the coefficients in the balanced chemical equation for combustion of acetone C3H6O in air  is 11

explanation

<h2>write a balanced chemical equation  for reaction</h2>

that is;  C3H6O + 4O2  → 3CO2 +3H2O

coefficient is the number in front of the chemical formula

the sum of coefficient is therefore= 1 ( in front of C3H6O) + 4 ( in front of O2) + 3 ( in front of CO2) + 3 ( in front of H2O) = 11

6 0
3 years ago
What is the equilibrium membrane potential due to na ions if the extracellular concentration of na ions is 142 mm and the intrac
Ganezh [65]

The equilibrium membrane potential is 41.9 mV.

To calculate the membrane potential, we use the <em>Nernst Equation</em>:

<em>V</em>_Na = (<em>RT</em>)/(<em>zF</em>) ln{[Na]_o/[Na]_ i}

where

• <em>V</em>_Na = the equilibrium membrane potential due to the sodium ions

• <em>R</em> = the universal gas constant [8.314 J·K^(-1)mol^(-1)]

• <em>T</em> = the Kelvin temperature

• <em>z</em> = the charge on the ion (+1)

• <em>F </em>= the Faraday constant [96 485  C·mol^(-1) = 96 485 J·V^(-1)mol^(-1)]

• [Na]_o = the concentration of Na^(+) outside the cell

• [Na]_i = the concentration of Na^(+) inside the cell

∴ <em>V</em>_Na =

[8.314 J·K^(-1)mol^(-1) × 293.15 K]/[1 × 96 485 J·V^(-1)mol^(-1)] ln(142 mM/27 mM) = 0.025 26 V × ln5.26 = 1.66× 25.26 mV = 41.9 mV

4 0
3 years ago
What is the volume of stank of nitrogen that contains 17 moles of nitrogen at 34 C under 12,000Pa?
Otrada [13]

Answer:

3626.76dm³

Explanation:

Given parameters:

Number of moles of Nitrogen in tank = 17moles

Temperature of the gas = 34°C

Pressure on the gas = 12000Pa

Unkown:

Volume of the tank, V =?

Converting the parameters to workable units:

We take the temperature from °C to Kelvin

K = 273 +  °C  = 273 + 34 = 307k

Taking the pressure in Pa to atm:

101325Pa = 1atm

12000Pa = 0.118atm

Solution:

To solve this problem, we employ the use of the ideal gas equation. The ideal gas law combines three gas laws which are the Boyle's law, Charles's law and the Avogadro's law.

            It is expressed as PV = nRT

The unknown is the Volume and we make it the subject of the formula

             V = \frac{nRT}{P}

Where R is called the gas constant and it is given as 0.082atmdm³mol⁻¹K⁻¹

Therefore  V = \frac{17 x 0.082 x 307 }{0.118} = 3626.76dm³

3 0
3 years ago
Read 2 more answers
Balance this chemical formula<br> Fe + Cl2 = FeCl3
san4es73 [151]
First you find out how much each element has

Fe=1 * 2                    Fe=1
Cl=2  *3                   Cl=3 *2

now we multiply each so we can balance each side.

So now we get our balanced equation
2 Fe + 3 Cl2 = 2 FeCl<span>3</span>
5 0
3 years ago
Read 2 more answers
2.In a titration, 25.00 cm3 of a solution of hydrochloric acid reacted with 18.40 cm3 of sodium hydroxide solution of concentrat
telo118 [61]

Answer:

0.11mol/dm³

Explanation:

The reaction expression is given as:

             HCl   +  NaOH  →  NaCl + H₂O

Volume of acid  = 25cm³  = 0.025dm³

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Concentration of base  = 0.15mol/dm³

Solution:

The concentration of hydrochloric acid = ?

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From the balanced reaction equation;

          1 mole of NaOH will combine with 1 mole of HCl

Therefore,  0.00276mol of the base will combine with  0.00276mol of HCl

 So;

  Concentration of acid  = \frac{number of moles }{volume}   = \frac{ 0.00276}{0.025}   = 0.11mol/dm³

4 0
3 years ago
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