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Greeley [361]
3 years ago
12

Calculate the percent by mass of a solution of Ca(NO3)2 that has 22.63 g dissolved in 896.92 g of water.

Chemistry
1 answer:
never [62]3 years ago
6 0

Hey there!

To calculate the percent by mass of the Ca(NO₃)₂ we need to find the total mass first by adding.

896.92 + 22.63 = 919.55

In total, the solution is 919.55 grams.

To find the percent of Ca(NO₃)₂ in the solution, divide the mass of Ca(NO₃)₂ by the total mass and multiply by 100.

22.63 ÷ 919.55 = 0.0246

0.0246 x 100 = 2.46

Ca(NO₃)₂ makes up 2.46% of the solution.

Hope this helps!

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For each ionic compound formula, identify the main group to which X belongs: (c) X2SO4.
Zinaida [17]

The answer is group 1A.

In the ionic compound formula X₂SO₄, SO₄ has a -2 charge. Hence to balance this -2 charge of SO₄, X must have a +1 charge.

Group 1A elements form X⁺ type of ions because they are metals. So, they have the tendency to lose electrons.

Hence, X must belong to the 1A group.

Ionic Compounds-

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6 0
1 year ago
At what pH are the moles of acid and base equal?
mihalych1998 [28]

Answer:

7

Explanation:

(Note: for a strong acid and strong base titration the equivalence point is at a pH=7. This is because at this point you have equal moles of added base as acid in the original solution. Therefore at the equivalence point the solution has formed a neutral salt and the pH is 7).

5 0
3 years ago
Read 2 more answers
Rolls of foil are 300mm wide and 2.020mm thick. (The density of foil is 2.7 g/cm^3). What maximum length of foil can be made fro
horrorfan [7]

Answer:  8556 mm, or 855.6 cm (8560 mm to 3 sig figs)

Explanation:  Convert mm to cm by dividing by 10 (1cm/10mm)

Find the area of the foil face in cm^2 (30cm*0.2020cm) = 0.606 cm^2

Calculate the volume occupied by 1.40 kg of foil in cm^3.  1.40kg = 1400g

1.400g/(2.7 g/cm^3) = 518.5 cm^3 for 1.40 kg Au

   Volume = Area (of the face) * Length  

We want Length:

Length = Volume/Area

L = (518.5 cm^3/0.606 cm^2)

L = 855.6 cm (8556 mm)  Round to 3 sig figs (856 cm and 8560 mm)

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2 years ago
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hope this helps!

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2 years ago
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