Answer:
The answer to your question is 5.5 x 10¹² kg/km³
Explanation:
Data
density = rho = X
mass = 5.94 x 10²⁴ kg
volume = 1.08 x 10¹² km³
Process
To solve this problem use the density formula and simplify it to find the result.
Formula
density = 
Substitution
density = 
Simplification and result
density = 5.5 x 10¹² kg/km³
This would be called the "Escape Velocity "
bobo mag isip ayaw mag aral bobi
Explanation:
bobo ka boboboboboob
Answer: 9.7 days
Explanation:
Applying Kepler's 3rd law, we can write the following proportion:
(Tm)² / (dem)³ = (Tsat)² / (dem/2)³
(As the satellite is placed in an orbit halfway between Erth's center and the moon's orbit).
Simplifyng common terms, and solving for Tsat, we have:
Tsat = √((27.3)²/8) = 9.7 days
1) Vf = Vo - gt; Vf = 0 => Vo = gt = 9.8m/s^2 * 1.5s = 14.7 m/s
2) d = Vo*t - gt^2 /2 = 14.7m/s*1.5 - 9.8m/s^2 * (1.5s)^2 / 2 = 11.02 m
