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AlekseyPX
3 years ago
9

Explain how to correctly add vectors in 2-D

Physics
1 answer:
Simora [160]3 years ago
8 0
To add vectors we can use the head to tail method (Figure 1).
Place the tail of one vector at the tip of the other vector.
Draw an arrow from the tail of the first vector to the tip of the second vector. This new vector is the sum of the first two vectors.
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One factor that drives atmospheric circulation is the movement of air from warm equatorial areas to cooler areas.
Debora [2.8K]

One factor that drives atmospheric circulation is the movement of air from warm equatorial areas to cooler areas.

This is true.


4 0
3 years ago
Read 2 more answers
Alkali Metals- 1 valence electron __________________&__________________.
Paraphin [41]
Hi , I think that the elements that have one valence electron and that are in the alkali metals  are the answers .
1.lithium
2.sodium
3.potassium
4.rubidium
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8 0
4 years ago
Help ASAP PLEASE.............:3​
Evgesh-ka [11]

Answer:

temperature measures heat - the unit is Celsius - and it is measured with a thermometer.

length is measuring how long, tall, or wide something is  - the base unit it metres - and it is measured with a ruler or a metre stick

volume is measuring the quantity of a three dimensional space - the unit is cubic centimetre - you find volume by taking the measurements with a ruler

mass is measuring how much space something takes up/ weight - unit is the gram - you use a scale

8 0
3 years ago
A traffic-safety engineer is designing a deceleration lane. She is basing the length of
Mice21 [21]

The deceleration of the car is observed as 2 m/s^2.

<h3>What is deceleration?</h3>

The term deceleration has to do with the decrease of velocity with time.

Given that;

v = 65 km/h or 18 m/s

u = 126 km/h to or 35 m/s

t = 8.5 s

a = ?

v = u - at

18 - 35 = -8.5a

a = 18 - 35/-8.5

a = 2 m/s^2

Learn ore about deceleration:brainly.com/question/4403243?

#SPJ1

7 0
2 years ago
Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that
kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.    

 

Explanation:

The Young's modulus is given by:

E = \frac{FL_{0}}{A\Delta L}

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

F = T_{w} = W_{o}

Where:

T_{w}: is the tension of the wire

W_{o}: is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

F = mg = 1700 kg*9.81 m/s^{2} = 16677 N

Hence, the Young's modulus is:

E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa          

Therefore, Young's modulus for the rope material is 20.8 MPa.                

I hope it helps you!                                    

7 0
3 years ago
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