A 31.0 kg crate, initially at rest, slides down a ramp 2.6 m long and inclined at an angle of14.0° with the horizontal. Using th
e work-kinetic energy theorem and disregarding friction, find the velocity of the crate at the bottom of the ramp.(g=10 m/s ^2
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Answer:
0.000234 seconds
Explanation:
Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m
We can start by calculating the angular speed of the rod:
Since one revolution equals to 2π rad. The speed in revolution per second must be
26800 / 2π = 4265 revolution/s
The number of seconds per revolution, or period, is the inverse:
1/4265 = 0.000234 seconds