A 31.0 kg crate, initially at rest, slides down a ramp 2.6 m long and inclined at an angle of14.0° with the horizontal. Using th
e work-kinetic energy theorem and disregarding friction, find the velocity of the crate at the bottom of the ramp.(g=10 m/s ^2
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Answer:
T=502.5N
Ax=171.8N
Explanation:
The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:
vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0
Now
horizontal forces sum = Ax - Tcos70
Now Moment about B
-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0
Ay=453.6N
Now substitute in sum of vertical forces T=502.5N
Ax=171.8N
