A 31.0 kg crate, initially at rest, slides down a ramp 2.6 m long and inclined at an angle of14.0° with the horizontal. Using th
e work-kinetic energy theorem and disregarding friction, find the velocity of the crate at the bottom of the ramp.(g=10 m/s ^2
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Answer:
Price=$7×10⁷
Explanation:
Step 1: Estimate the volume of the pile,
Step 2: Multiply it by the density to get its mass
Step 2: Then multiply the mass by the price per gram to get the total price
So
The average pile dimensions are=45.7×45×172.7
Price=m×$10
Price=(7×10⁶)×$10
Price=$7×10⁷
Answer:
v =
Explanation:
For this exercise we must use the projectile launch ratios, let's start by finding the time it takes to reach the bottom of the cliff, the initial vertical velocity is zero
y = y₀ + t - ½ g t²
at the bottom of the cliff y = 0 and as the body is thrown horizontally the initial vertical velocity is zero
0 = y₀ + 0 - ½ g t²
t =
this time is the same as the horizontal movement.
Let's use Newton's second law to find the acceleration on this x-axis due to the force of the air
F = m aₓ
they tell us that force is equal to the weight of the body
-mg = maₓ
aₓ = -g
the sign indicates that the acceleration is to the left
we write the kinematics equation
x = x₀ + v₀ₓ t + ½ aₓ t²
They indicate that the final position is the foot of the cliff (x = 0), when it leaves the top it is at x₀ = 0 and has a velocity v₀ₓ = v
we substitute
0 = 0 + v t + ½ (-g) t²
v = ½ g t
we use the drop time
v = ½ g
v =