Answer:
(a) I_A=1/12ML²
(b) I_B=1/3ML²
Explanation:
We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².
(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².
(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:
Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:
Finally, using the Parallel Axis Theorem, we calculate I_B:
Answer:
D
Explanation:
im guessing here i hope it is correct and good luck
<span> - </span><span>a 10 </span>m<span> long wire of mass of 123g is </span>stretched<span> under a tension of 255N. a </span>generated<span> at</span>one end<span> and 20ms later a second </span>pulse<span> is </span>generated<span> at the opposite </span>end where n = mass of the wire / length = 123 x 10^-3<span> /10 = 1.23 kg/</span>m<span> v = √(255/1.23) = 14.4 </span>m/<span>s</span>
The correct answer for the question that is being presented above is this one: "c. elastic." Most earthquakes are produced by the rapid release of
<span>elastic energy stored in rocks s</span>ubjected to great forces. The greater the elasticity of the energy, the more it is subjected to great forces.
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