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Illusion [34]
3 years ago
15

A football player runs down the field at a speed of 8 m/s how long will it take him to run 20 m?

Physics
1 answer:
shepuryov [24]3 years ago
4 0
The answer is simple. Since the football player runs at 8m/s and you are trying to find out how long it will take him to run 20 m, you simply divide 20/8.

The answer to this would be 2.5 seconds for the football player to run 20 meters.
I hope I did this problem correct and I hope that this helped you :)))
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When sinkholes expand, creating isolated towers of rock, what is occurring?
Illusion [34]

Im pretty sure the answer is D, I may be wrong tho

4 0
3 years ago
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A uniform bridge 20.0 m long and weighing 400000 N is supported by two pillars located 3.00 m from each end. If a 19600 N car is
Svetradugi [14.3K]

Answer:

P = 238475 N

Q = 181125

Explanation:

From the diagram attached below,

For the bridge to be at equilibrium,

Sum of upward force = sum of downward force

P+Q = 400000+19600

P+Q = 419600.................. Equation 1

Taking  moment about support A

sum of clockwise moment = sum of anti clockwise moment.

400000(10-3)+19600(8-3) = Q(20-6)

2800000+98000 = 16Q

2898000 = 16Q

Q = 2898000/16

Q = 181125 N.

Substitute the value of Q into equation 1

P+181125 = 419600

P = 419600-181125

P = 238475 N.

Hence, support A exert a force of 238475 N and support B exert a force of 181125 N

7 0
3 years ago
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Suppose you lived in the crater Copernicus on the side of the Moon facing Earth.
Wittaler [7]

Answer and Explanation:

In case, I lived in the Crater Copernicus on Moon's side facing the Earth then:

  • On moon, as it orbits the Earth, it takes 29 and a half days to complete one cycle of sunrise and sunset. So, the would rise once in 29 and a half day.
  • The moon orbits the Earth in such a way that the its same side faces the Earth always which concludes that the Earth is overhead every time resulting in no Earth rise or Earth set on Moon.
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5 0
3 years ago
9. A car driver brakes gently. Her car slows down front --
sleet_krkn [62]

Answer:

9) This is a case of deceleration

10)-0.8 ms-2

b) acceleration is the change in velocity with time

11)

a) 100 ms-1

b) 100 seconds

12) 10ms-1

13) more information is needed to answer the question

14) - 0.4 ms^-2

15) 0.8 ms^-2

Explanation:

The deceleration is;

v-u/t

v= final velocity

u= initial velocity

t= time taken

20-60/50 =- 40/50= -0.8 ms-2

11)

Since it starts from rest, u=0 hence

v= u + at

v= 10 ×10

v= 100 ms-1

b)

v= u + at but u=0

1000 = 10 t

t= 1000/10

t= 100 seconds

12) since the sprinter must have started from rest, u= 0

v= u + at

v= 5 × 2

v= 10ms-1

14)

v- u/t

10 - 20/ 25

10/25

=- 0.4 ms^-2

15)

a=v-u/t

From rest, u=0

8 - 0/10

a= 8/10

a= 0.8 ms^-2

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Lungs is what helps u breath

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