Question

The number of windings on the primary coil of a transformer

Answer 1

Answer:

I. Vs = 8.0 Volts.

II. Is = 4.5 Amperes.

Explanation:

Given the following data;

Np = 1.5Ns = $\frac {N_{P}}{N_{S}} = 1.5$  ..... equation 1

Ip = 3.0 A

Vp = 12 V

To find the voltage and current on the secondary coil;

I. For the voltage in the secondary coil (Vs), we would use the following formula;

$\frac {V_{P}}{V_{S}} = \frac {N_{P}}{N_{S}}$  ...... equation 2.

Substituting eqn 1 into eqn 2, we have;

$\frac {V_{P}}{V_{S}} = 1.5$

$\frac {12}{V_{S}} = 1.5$

Cross-multiplying, we have;

$V_{S} * 1.5 = 12$

$V_{S} = \frac {12}{1.5}$

Vs = 8.0 V

II. For the current in the secondary coil (Is), we would use the following formula;

$\frac {I_{S}}{I_{P}} = \frac {N_{P}}{N_{S}}$  .... equation 3

Substituting eqn 1 into eqn 3, we have;

$\frac {I_{S}}{I_{P}} = 1.5$

$\frac {I_{S}}{3.0} = 1.5$

Cross-multiplying, we have;

$I_{S} = 1.5 * 3.0$

Is = 4.5 A