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3 years ago

6CO2 + 6 H2O —> C6H12O6 + 6O2

Chemistry

1 answer:

PilotLPTM [1.2K]3 years ago

3 0

Answer:

The answer to your question is 0.5 moles

Explanation:

Data

moles of Glucose = ?

moles of carbon dioxide = 3

Balanced chemical reaction

6CO₂ + 6H₂O ⇒ C₆H₁₂O₆ + 6O₂

Process

To solve this problem, use proportions, and cross multiplication.

Use the coefficients of the balanced equation.

6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆

3 moles of CO₂ ---------------- x

x = (3 x 1) / 6

-Simplification

x = 3/6

-Result

x = 0.5 moles of Glucose

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How do you know if a reaction is endothermic

Karo-lina-s [1.5K]

If the temperature rises in a reaction. Exothermic is if it loses heat.

Have a nice day, brainliest would be fantastic.

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3 years ago

Which compounds are classified as Arrhenius acids?

Olenka [21]

Answer:The correct answer is option 4.

Explanation:

Arrhenius acids are those compounds which gives $H^+$ ions when dissolved in their aqueous solution.

$HA(aq)\rightarrow H^++A^-$

Arrhenius bases are those compounds which gives $OH^-$ ions when dissolved in their aqueous solution.

$BOH(aq)\rightarrow OH^-+B^+$

$HBr \& H_2SO_4$ are Arrhenius acids because they form $H^+$ ions in their respective aqueous solution.

$HBr(aq)\rightarrow H^++Br^-$

$H_2SO_4(aq)\rightarrow 2H^++SO_{4}^{2-}$

Hence, the correct answer is option 4.

6 0

3 years ago

Read 2 more answers

How does the A Hreaction relate to the A He of molecules involved in a reaction?

igor_vitrenko [27]

Answer:

B. ΔHreaction = ΔH°f reactants- ΔH°f products

Explanation:

Using Hess's law, it is possible to sum ΔH of several related reactions to find ΔH of a particular reaction.

Having in mind Hess's law, ΔH°f is defined as the change in enthalpy during the formation of 1 mole of substance from its constituent elements (That is, pure elements, mono or diatomics, that have a ΔH° = 0).

For example, in ΔH°f of H₂O, the equation is:

H₂(g) + 1/2O₂(g) → H₂O(g)

The constituent elements with ΔH°f = 0 are H₂(g) and O₂(g).

Now, using Hess's law, you can sum the ΔH°f of substance in a reaction as, for example:

NaOH + HCl → H₂O + NaCl. ΔHr

The ΔH°f for each substance in the reaction is:

NaOH: Na + 1/2H₂ + 1/2O₂ → NaOH (1)

HCl: 1/2H₂ + 1/2Cl₂ → HCl (2)

H₂O: H₂ + 1/2O₂ → H₂O (3)

NaCl: Na + 1/2Cl₂ → NaCl (4)

The algebraic sum of (3) + (4) is -(ΔH°f reactants):

H₂ + 1/2O₂ + Na + 1/2Cl₂ → NaCl + H₂O ΔH°f reactants

This reaction - {(1)+(2)} ΔH°f products

NaOH + HCl → H₂O + NaCl.

ΔHr = ΔH°f reactants- ΔH°f products

In the example, we obtain this relationship that can be expanded for all reactions. Thus, right answer is:

<h3>B. ΔHreaction = ΔH°f reactants- ΔH°f products</h3>

8 0

3 years ago

Acetic acid (HC2H3O2) is the active ingredient in vinegar. Calculate the mass percent composition of O in acetic acid.

skelet666 [1.2K]

Answer:

53.29% of acetic acid is Oxygen

Explanation:

Step 1: Given data

Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.

Step 2: the molar masses

The molecular mass of acetic acid is:

4* H = 4* 1.01 g/mole

2* C = 2*12 g/mole

2*O = 2* 16 g/mole

Total molar mass = 4+ 24+32 = 60.052 g/mole

Step 3: Calculate the mass percent

32 g of the 60.052 g is Oxygen

(32/60.052) *100% = 53.29%

53.29% of acetic acid is Oxygen.

7 0

3 years ago

Read 2 more answers

What are the four rules for significant figures

kkurt [141]

Answer:

Significant Figures

Explanation:

1) Annotation category: ...

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5)Leading zeros are NOT significant. ...

6)Trailing zeros to the right of the decimal ARE significant. ...

7)Trailing zeros in a whole number with the decimal shown ARE significant. 8) to make you happy :) hope this helps you :)

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3 years ago