Answer:1 two elements and both are nonmetals.
Explanation:
Answer:
Over time, the solid particles will settle on whatever is outside."
Explanation:
Answer:
19.20 g. Explanation: ∵ mass % = [mass of solute/mass of solution] x 100
The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
The balanced reaction of the given condition as follow :
Ca(OH)₂ + 2HC₂H₃O₂ ------> Ca(C₂H₃O₂)₂ + 2H₂O
from the equation it is clear that stoichiometry of Ca(OH)₂ is 1 and the stoichiometry of HC₂H₃O₂ is 2. therefore the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
Thus, The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
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Answer:
There are 198 grams of iron in a 450-gram sample of the ore.
Explanation:
From the given information:
Given that:
100-gram sample of iron ore is found in 44g of iron.
Thus. the grams of iron that can be found in a 450-gram sample of the iron ore can be computed as follows:
100g of iron ore = 44g of iron
450 gram of iron ore = x g of iron
x(g) of iron = ( 44g of iron × 450 gram of iron ore) / 100g of iron ore
x(g) of iron = 198 grams of iron
Thus, there are 198 grams of iron in a 450-gram sample of the ore.