An object in equilibrium has no NET force acting on it. It's acceleration is zero, meaning that it's moving in a straight line with constant speed (which may be zero).
Answer:
D
Explanation:
The wavelength of A falls in the range of 700 nanometers to 1 millimeter. It is Infra red
The wavelength of B falls in the range of 450 nanometers to 740 nanometers. It is visible light
The wavelength of C falls in the range of 10 nanometers to 400 nanometers. It is Ultraviolet.
The wavelength of D falls in the 0.01 nanometers to 10 nanometers. It is x ray.
From the ohms law resistance is given by dividing the amount of current by the potential difference (voltage). In a circuit resistors may be arranged in series or parallel which determines the total effective resistance of the circuit depending on the arrangement used.
When resistance are in parallel we apply the formula 1/Rt=1/R1 +1/R2 where Rt is the total resistance, R1 resistance of the first resistor and R2 the resistance of the second resistor.
therefore, 1/Rt = 1/10 +1/10 =2/20 which when simplified is 1/10, therefore 1/Rt is 1/10, to get Rt we do the reciprocal to get 10 ohms.
Therefore the effective resistance of the combined resistors in parallel is 10 ohms
Answer:
(a). The thickness of the glass is 868 nm.
(b). The wavelength is 3472 nm.
Explanation:
Given that,
Refractive index = 1.20
Wavelength = 496 nm
Next wavelength = 386 nm
We need to calculate the thickness of the glass
Using formula for constructive interference

Put the value into the formula
In first case,
.....(I)
In second case,

.....(II)
From equation (I) and (II)



Put the value of m in equation (I)


The thickness of the glass is 868 nm.
(b). We need to calculate the wavelength
Using formula of constructive interference


Put the value into the formula


Hence, (a). The thickness of the glass is 868 nm.
(b). The wavelength is 3472 nm.
The calculated mutual inductance is 8.544 x 10⁻⁵ H.
Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.
Length of the solenoid= 5.0 cm
Area of cross-section=1.0 cm²
no of spaced turns=300 turns
turns of insulated wire=180 turns
Mutual inductance (M) = μ₀μr N1N2 A/ L
=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5
=79.12 x 10⁻¹⁰ x 54000 / 5
=8.544 x 10⁻⁵ H
hence, the mutual inductance is 8.544 x 10⁻⁵ H.
Learn more about Mutual inductance here-
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