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3 years ago

How many particles are in 7.07x10^-6 moles of a substance?

Chemistry

1 answer:

Butoxors [25]3 years ago

5 0

Answer:

4.25*10^18

Explanation:

1 mole =6.023*10^23 particles

so 7.07*10^-6 mole=6.023*10^23*7.07*10^-6 particles=4.25*10^18 particles

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A sample of gas has a volume of 16.0 liters at a pressure of 0.5 atmospheres. When the volume decreases to 4.0 liters at a const

Stella [2.4K]

Answer:

2 atm

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 16.0 L

Initial pressure (P₁) = 0.5 atm

Final volume (₂) = 4 L

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

0.5 × 16 = P₂ × 4

8 = P₂ × 4

Divide both side by 4

P₂ = 8 / 4

P₂ = 2 atm

Thus, the final pressure of the gas is 2 atm

5 0

3 years ago

A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder

Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

$PV_1=nRT$

where,

P = pressure of gas = 1 atm

$V_1$ = volume of gas = ?

T = temperature of gas = $270^oC=273+270=543K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K$

$V_1=9.12L$

Now we have to calculate the volume at 24°C.

$PV_2=nRT$

where,

P = pressure of gas = 1 atm

$V_2$ = volume of gas = ?

T = temperature of gas = $24^oC=273+24=297K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K$

$V_2=4.99L$

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 9.12 L

$V_2$ = final volume = 4.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (4.99-9.12)L$

$w=4.13L.artm=4.13\times 101.3J=418.4J$

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0

3 years ago

Why is it that the higher the molecular mass of the alkane, the higher the boiling point? Refer to intermolecuar forces and ener

AnnZ [28]

Answer:

Higher melting and boiling points signify stronger noncovalent intermolecular forces. Consider the boiling points of increasingly larger hydrocarbons. More carbons means a greater surface area possible for hydrophobic interaction, and thus higher boiling points.

3 0

3 years ago

What are cathode rays

Llana [10]

Answer:

a beam of electrons emitted from the cathode of a high-vacuum tube.

Explanation:

4 0

3 years ago

Please help me, Thank you!

Phantasy [73]

Answer:

Explanation:

The atom shown in the image has 2 core electrons.

Electrons are the negatively charged particles within an atom. Therefore the total number of electrons surrounding the nucleus in the given specie is 7.

So;

We have 2 core electrons

And 5 valence electrons

The core electrons are the inner orbital electrons.

The valence electrons are the outermost electrons.

3 0

3 years ago