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baherus [9]
3 years ago
13

The picture shows a natural environment.

Chemistry
2 answers:
Marta_Voda [28]3 years ago
6 0

Answer: The answer is B

Explanation: cause the bush and cactus are plants and they are living things and rat and snake are animal which is also living thing

oee [108]3 years ago
5 0

Answer:

b.

Explanation:

i took the test

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C=h/[M(T2-T1)] solve for T1
vodka [1.7K]

Explanation:

This is expressing as a subject of a formula of a specie.

This equation is used in solving for specific heat capacity of a material;

     equation:

         c = \frac{h}{M(T2 - T1)}

First cross multiply:

  c[M(T2 - T1)]  = h

Then multiply both sides by \frac{1}{c } :

\frac{1}{c }  x    c[M(T2 - T1)]   = \frac{1}{c }  x h

        M(T2 - T1) = \frac{h}{c}

Multiply both sides by \frac{1}{M}

\frac{1}{M}   x   M(T2 - T1)  = \frac{1}{M} x  \frac{h}{c}

    T2 - T1 = \frac{h}{Mc}

Now rearrange to produce;

    T1 = T2 + \frac{h}{Mc}

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

7 0
4 years ago
If electrons were used in the two slit experiment instead of light, what change would need to be made to the slit spacing in ord
irina [24]
The change that would need to be made to the slit spacing in order to see a diffraction pattern is bending, because in understanding why light behaves like a wave, it is the interference and diffraction were the phenomena distinguish waves from particles but waves are the only one can interfere and diffract while particles do not. The light bends around obstacles or cylinder like waves do, then it is bending which cause and resulted in the single slit diffraction pattern. 
5 0
3 years ago
A 19.0 g piece of metal is heated to 99.0 °C and then placed in 150 mL of water at 21°C. The temperature of the water rose to 23
Anna35 [415]

Answer:

0.8696\ \text{J/g}^{\circ}\text{C}

Explanation:

m_m = Mass of metal = 19 g

c_m = Specific heat of the metal

\Delta T_m = Temperature difference of the metal = 99-23=76^{\circ}\text{C}

V = Volume of water = 150 mL = 150\ \text{cm}^3

\rho = Density of water = 1\ \text{g/cm}^3

c_w = Specific heat of the water = 4.186 J/g°C

\Delta T_w = Temperature difference of the water = 23-21=2^{\circ}\text{C}

Mass of water

m_w= \rho V\\\Rightarrow m_w=1\times 150\\\Rightarrow m_w=150\ \text{g}

Heat lost will be equal to the heat gained so we get

m_mc_m\Delta T_m=m_wc_w\Delta T_w\\\Rightarrow c_m=\dfrac{m_wc_w\Delta T_w}{m_m\Delta T_m}\\\Rightarrow c_m=\dfrac{150\times 4.186\times 2}{19\times 76}\\\Rightarrow c_m=0.8696\ \text{J/g}^{\circ}\text{C}

The specific heat of the metal is 0.8696\ \text{J/g}^{\circ}\text{C}.

4 0
3 years ago
A student reports the following measurements for a set of pennies: 102.0mL, 91.0 g. What is the density of the pennies.
zysi [14]

Answer:

V = 102.0 ml

m = 91.0 ml

density = ...?

density = m / V

= 91.0 / 102.0

= 0.89215 g/ml

7 0
3 years ago
Which of these best describes the particle motion taking place as CO2 gas is exposed to freezing temperatures?
mote1985 [20]
CO2 is carbon dioxide which is most famous for being in gas form so i would figure if it was exposed to freezing temperatures it would turn into a liquid then maybe a solid<span />
5 0
3 years ago
Read 2 more answers
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