Answer:
The answer is
<h2>720 Joules</h2>
Explanation:
The kinetic energy of a body can be found by using the formula
<h3>
![K.E = \frac{1}{2} {mv}^{2}](https://tex.z-dn.net/?f=K.E%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%7Bmv%7D%5E%7B2%7D%20)
</h3>
where
m is the mass
v is the velocity / speed
From the question
mass = 10 kg
velocity = 12 m/s
Substitute the values into the above formula and solve
That's
<h3>
![KE = \frac{1}{2} \times 10 \times {12}^{2} \\ = 5 \times 144 \: \:](https://tex.z-dn.net/?f=KE%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%2010%20%5Ctimes%20%20%7B12%7D%5E%7B2%7D%20%20%5C%5C%20%20%20%3D%205%20%5Ctimes%20144%20%20%5C%3A%20%20%5C%3A%20)
</h3>
We have the final answer as
<h3>720 Joules</h3>
Hope this helps you
Answer:)
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Answer:
Percentage lithium by mass in Lithium carbonate sample = 19.0%
Explanation:
Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g
Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g
Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%
Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g
Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%
Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g
mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g
Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%
Percentage lithium by mass in Lithium carbonate sample = 19.0%
Answer:
2.76 (full answer) 2.7617e-6
Explanation:
Answer: - 436.5 kJ.
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.
The given chemical reaction is,
![\Delta H_1=873kJ](https://tex.z-dn.net/?f=%5CDelta%20H_1%3D873kJ)
Now we have to determine the value of
for the following reaction i.e,
![\Delta H_2=?](https://tex.z-dn.net/?f=%5CDelta%20H_2%3D%3F)
According to the Hess’s law, if we divide the reaction by half then the
will also get halved and on reversing the reaction , the sign of enthlapy changes.
So, the value
for the reaction will be:
![\Delta H_2=\frac{1}{2}\times (-873kJ)](https://tex.z-dn.net/?f=%5CDelta%20H_2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%28-873kJ%29)
![\Delta H_2=-436.5kJ](https://tex.z-dn.net/?f=%5CDelta%20H_2%3D-436.5kJ)
Hence, the value of
for the reaction is -436.5 kJ.