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3 years ago

Someone who knows how to do this please help me!!!!!

Chemistry

1 answer:

Sindrei [870]3 years ago

5 0

It may just be my internet but the picture is just white. maybe try reposting this..?

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A chemist is making 200 l of a solution that is 62% acid. he is mixing an 80% acid solution with a 30% acid solution. how much o

Savatey [412]

Answer: 72L of 30% and 128L of 80%

You can determine the weight of the acid by multiplying the concentration with the volume. Let say v1 is the volume of 30% solution needed and v2 is the volume of 80% solution.
The weight of acid from the used solution should be equal to the product. You can get this equation
final solution= solution1 + solution2
200l * 62%= v1 * 30% + v2*80%
124L= 0.3v1 + 0.8v2
124L- 0.3v1= 0.8v2
v2=155L- 0.375v1

The total volume of both should be 200l. If you use the previous equation, you can calculate:
v1+v2=200L
v1+ (155L- 0.375v1)= 200L
0.625v1= 200L - 155L
v1= 45/ 0.625= 72L

v1+v2=200L
v2= 200L- 72L= 128L

5 0

3 years ago

What are the source of error in determination of boiling point and melting point

Neko [114]

purity of the substance is usually the main error (for example: water with impurities will have m.p. less than 273K or 0 degree celcius while it's b.p. will be greater than 373K or 100 degree celcius). 
-> air/ room temperature (it takes longer to cook in mountains and shorter at beaches) 
-> parallax error (error by determining the meniscus of the thermometer) 
and many more..

7 0

3 years ago

Copper has average atomic mass of 63.546 amu. It's two isotopes are Cu-63 (which is 69.17% abundant and has a mass of 62.9296 am

garri49 [273]

Answer: 69.152% → 63^Cu

30.848% → 65^Cu

Explanation:

As you know, the average atomic mass of an element is determined by taking the weighted average of the atomic masses of its naturally occurring isotopes.

Simply put, an element's naturally occurring isotopes will contribute to the average atomic mass of the element proportionally to their abundance.

Explanation:

6 0

3 years ago

2C3H7OH + 9O2 --> 6CO2 + 8H2O

UNO [17]

Answer 12.2g is the answer

4 0

3 years ago

At a temperature of 273 K, a 400.-milliliter gas sample has a pressure of 760. millimeters of mercury. If the pressure is change

KatRina [158]

Answer:

188.03K

Explanation:

The following data were obtained from the question:

T1 (initial temperature) =273K

V1 (initial volume) = 400mL

P1 (initial pressure) = 760mmHg

P2 (final pressure) = 380mmHg

V2 (final volume) = 551mL

T2 (final temperature) =?

Applying the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas can be obtained as follow:

P1V1/T1 = P2V2/T2

760 x 400/273 = 380 x 551/T2

Cross multiply to express in linear form as shown below:

760 x 400 x T2 = 273 x 380 x 551

Divide both side by 760 x 400

T2 = (273 x 380 x 551)/(760 x 400)

T2 = 188.03K.

Therefore, at a temperature of 188.03K, the gas sample will have a volume of 551mL

3 0

4 years ago