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3 years ago

The answer for this question i'm confused

Physics

1 answer:

lorasvet [3.4K]3 years ago

8 0

Answer:

it looks like they are embracing eachother, so i would say the bottom right corner

Explanation:

You might be interested in

The Earth's magnetic field protects the planet from _____.

OLga [1]

The answer you're looking for is the last option. "ultraviolet radiation." Hope this proves helpful!

8 0

3 years ago

To reduce auto emissions in the United States, modifications to automobile engines have been required since the 1960s.

natali 33 [55]

Answer:

True

Explanation:

8 0

2 years ago

An ideal heat engine absorbs heat at 100°C and exhausts heat at 0°C. What is its percent efficiency?

vampirchik [111]

Answer:

26.8 %

Explanation:

TH = 100°C = 100 + 273 = 373 K

Tc = 0°C = 273 K

The efficiency of the heat engine is given by

$\eta = 1-\frac{T_{c}}{T_{H}}$

$\eta = 1-\frac{273}{373}$

η = 0.268

η = 26.8 %

Thus, the efficiency of the heat engine is 26.8 %.

6 0

3 years ago

The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivi

ahrayia [7]

To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

$R = \rho \frac{L}{A}$

Where,

R= Resistance of the conductor

$\rho =$ Resistivity of the conductor material

L = Length

A = Cross-sectional area of conductor

With the previous values the area of the muscle (Real Muscle-82%)is,

$A_m = (0.82)\pi r^2 = (0.82)\pi (12/2*10^{-2})^2$

$A_m = 9.274*10^{-3}m^2$

Using the equation from Resistance we have that at the muscle the value is:

$R_m = \rho \frac{L}{A}$

$R_m = \frac{13*(0.4)}{9.274*10^{-3}}$

$R_m = 560.70\Omega$

At the same time we can make the same process to calculate the resistance of the fat, then

$A_m = (0.18)\pi r^2 = (0.18)\pi (12/2*10^{-2})^2$

$A_m = 2.0357*10^{-3}m^2$

The resistance of the fat would be,

$R_f = \rho \frac{L}{A}$

$R_f = \frac{25*(0.4)}{2.0357*10^{-3}}$

$R_f = 4912.3\Omega$

Then the total resistance in a set as the previously writen, i.e, in parallel is:

$R=\frac{R_mR_f}{R_m+R_f}$

$R = \frac{(560.70)(4912.3)}{4912.3+560.70}$

$R = 502.62\Omega$

We can here apply Ohm's law, then

$I= \frac{V}{R}$

$I = \frac{1.5}{502.62}$

$I = 2.984*10^{-3}A$

$I = 2.984mA$

3 0

4 years ago

What is the average velocity of a rocket that travels 15 m in 0.25 seconds?

Brrunno [24]

Answer:

<em><u>60 m/s</u></em>

Explanation:

Average Speed = Distance/ Time

= 15/0.25 = 60m/s

5 0

4 years ago