Answer:
A. How much matter an object has, plus the magnitude and direction of its motion
Explanation:
Momentum is defined as the product of mass by velocity, in the international system of measurements (SI) momentum has the following Units [kg*m/s].
P = m*v
where:
P = momentum Lineal [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Therefore the answer is A) How much matter an object has, plus the magnitude and direction of its motion
Answer: The magnitude of the velocity = 2/5 m/s
Explanation:
In this question, the magnitude of the velocity is the product of the magnitude of the displacement vector and the magnitude of the component of the velocity that acts in the direction of displacement.
This will be a scalar projection of V onto X
Please find the attached files for the solution
Answer:

Explanation:
Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass
at a distance r will be:

where
is the gravitational constant.
This force is the centripetal force the satellite experiments, so we can write:

Putting all together:

which means:
![r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BGM%7D%7B4%5Cpi%5E2%7DT%5E2%7D)
Which for our values is:
![r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B%286.67%5Ctimes10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%286.39%5Ctimes10%5E%7B23%7D%20kg%29%7D%7B4%5Cpi%5E2%7D%281.026%5Ctimes24%5Ctimes60%5Ctimes60s%29%5E2%7D%3D20395282m%3D20395.3km)
Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km
, which leaves us with:
