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kolezko [41]
3 years ago
8

Which of the following chemical equations demonstrates that atoms are conserved during a chemical reaction?

Physics
1 answer:
mr_godi [17]3 years ago
8 0

Answer:

2Mg + O2 → 2MgO

Explanation:

this is what your looking for

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The illuminance due to a 60.0-w lightbulb at 3.0m is 9.35 lx. What is the total luminous flux of the bulb
Furkat [3]
The equation for luminous flux is given as P = 4\pir^{2}E
where P is the luminous flux, r is the distance and E is the illumination. The unit for P is lumen, E is lux and r is in meters. Substituting the given to the equation:

P = 4\pir^{2}E 

P= 4\pi(3)^{2}(9.35) = 1057.46 lumens (lm)

The total luminous flux is equal to 1057.46 lumens (lm).
3 0
3 years ago
As the speed/velocity of an object increases what happens to the kinetic energy of the object
Elanso [62]
The kinetic energy increases
8 0
3 years ago
Read 2 more answers
What two things does light provide?
labwork [276]

Answer:

Light provides brightness to see and also light carries energy

5 0
3 years ago
In which situation is maximum work considered to be done by a force?
umka2103 [35]

Answer:

A) When the angle between the Force (F) and Displacement (x) is 0°, because, Work done (W) is directly proportional to the Cosine of the Angle between the Force applied and the resultant displacement of the subject.

W = F•x cos ∅

If ∅ = 0°,

W = F•x ===> Maximum Work Done.

If ∅ = 45°,

W = F•x/√2

If ∅ = 90°,

W = 0

If ∅ = 180°,

W = –F•x ===> Minimum Work Done.

7 0
3 years ago
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 34.5
Inessa05 [86]

Answer:

the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Explanation:

Given;

initial velocity of the airplane. u = 34.5 m/s

distance traveled by the airplane, s = 46,100 m

final velocity of the airplane, v = 40.7 m/s

The acceleration of the airplane is calculated from the following kinematic equation;

v² = u² + 2as

2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²

5 0
3 years ago
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