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3 years ago

What is the electric flux φ through each of the six faces of the cube? Use ϵ0 for the permittivity of free space?

Physics

1 answer:

exis [7]3 years ago

3 0

If total charge Q is enclosed in the surface of cube

then we will have say that total flux linked with all surfaces of the cube will be given by

$\phi = \frac{Q}{\epsilon_0}$

since the position of charge is symmetric with respect to the center of the cube so here this whole flux will be equally linked with each of the face of the cube

So here total 6 faces of the cube is there and the total flux of the charge will equally divide in these 6 faces

so flux linked with each face is given by formula

$\phi = \frac{Q}{6\epsilon_0}$

so each face will have above flux due to central position of charge Q

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A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and t

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A) The net force on the motorbike is 205.9 N

B) The acceleration of the motorbike is $1.37 m/s^2$

C) The final speed is 5.2 m/s

D) The elapsed time is 3.80 s

Explanation:

There are two forces acting on the motorbike:

- The applied force, F = 250 N, forward

- The frictional force, $F_f$ , backward

The frictional force can be written as

$F_f = \mu mg$

where

$\mu=0.03$ is the coefficient of kinetic friction

$m=150 kg$ is the mass of the motorbike

$g=9.8 m/s^2$ is the acceleration of gravity

Therefore the net force is given by

$\sum F = F - F_f = F - \mu mg$

And substituting, we find

$\sum F=250 - (0.03)(150)(9.8)=205.9 N$

The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:

$\sum F = ma$