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3 years ago

If an atom has the same amount of protons and electron, its net charge will be

Chemistry

2 answers:

kolezko [41]3 years ago

4 0

Positive or natural

DiKsa [7]3 years ago

3 0

I’m pretty sure the answer would be natural

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Three radioisotopes are being discussed in a chemistry class. Technetium-99m has a half-life of 6 hours. Rubidium-87 has a half-

8_murik_8 [283]

A likely application of a radioactive isotope with a short half-life such as Technetium-99 will be as a medical tracer. It will likely be used by a doctor to check the movement of substances within a person's body.

A radioactive isotope with such a long half-life like Rubidium-87 is likely used in the determination of the age of fossils and artifacts found by archaeologists.

5 0

3 years ago

Read 2 more answers

If scientists had tried to repeat thomosons experiment and found that they could not would thomosons cocnclusion still have been

lesantik [10]

Answer:

Explanation:

The conclusions from Thomoson's claims would be invalid if his experiment could not be replicated.

One of the attributes of a valid experiment in science is replication. That is, an experiment must be repeatable with similar outcomes under similar conditions as the original experiment when independently performed by another scientist. Once an experiment cannot be replicated, the outcomes of such an experiment become invalid in science.

Hence, Thomoson's conclusion would be invalid if his experiment could not be replicated.

5 0

3 years ago

Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.

bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr (1)

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = 181,66 kJ/mol

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = 0,216 kJ/Kmol

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ 4. +117,1 kJ/mol

I hope it helps!

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3 years ago

True or false? Second level consumers may be carnivore or omnivores

const2013 [10]

Yes this is true because they are able to consume 2 organisms which are plants and animal just like us.

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3 years ago

How is the filter bed cleaned

siniylev [52]

Answer:

The filter bed is cleaned by occasional backwashing ;-; im sorry if this isn't a great answer but I tried

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2 years ago