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patriot [66]
3 years ago
13

Energy can transform between different types. For each of the following examples, identify two energy transformations and the ty

pes of energy involved in the transformations: Cannonball fired upward from a cannon Diver jumping from a spring board Squirrel jumping from a tree and landing on the net of a trampoline
Physics
1 answer:
Jet001 [13]3 years ago
7 0

1. Cannonball fired upward from a cannon

here in this cannon we can say kinetic energy is converted into potential energy of the cannon.

here this is because when cannon ball is shot with some speed its kinetic energy is converted into potential energy at the top point of its path

2. Diver jumping from a spring board

when diver is jumping on spring board then spring potential energy is converted into kinetic energy of the diver.

here when spring is compressed the energy in it is in the form of spring potential energy while at the other form it is converted into kinetic energy of the diver when he jump off.

3. Squirrel jumping from a tree and landing on the net of a trampoline.

When squirrel is jumping from tree and landing on the net trampoline the gravitational potential energy of the squirrel will transform into the kinetic energy of squirrel and then it is transformed into the potential energy of the net trampoline.

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You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of
Alecsey [184]

Answer:

18 newtons

Explanation:

Divide weight by speed

3 0
3 years ago
4. A trolley of mass 2kg rests next to a trolley of mass 3 kg on a flat
nydimaria [60]

Answer:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. The total momentum of the trolleys after separation is zero

c. The momentum of the 2 kg trolley after separation is 12 kg·m/s

d. The momentum of the 3 kg trolley is -12 kg·m/s

e. The velocity of the 3 kg trolley = -4 m/s

Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0

c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s

d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s

e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley

∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s

The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s

3 0
3 years ago
White light is incident on a diffraction grating. What color is the central maximum of the interference pattern?
lara [203]

Answer:

The color of the central maximum is white.

Explanation:

A diffraction grating in optics is generally known as an optical component that contains a periodic structure. It is commonly used to breakdown and diffract light into different beams that move in several directions. For example, if a light ray is allowed to pass through the component (i.e. diffraction grating), the   central maximum will have a white color.

8 0
3 years ago
calculate the weight of an object of mass 100 kg on the surface of a Planet whose mass and diameter are 4.8*10^24 kg and 12000km
PilotLPTM [1.2K]

The weight of an object mass of 100 kg on the surface of a Planet willl is 981 N.

<h3>What is weight?</h3>

The weight of matter is found as the product of the mass and the gravitational acceleration;

Given data;

Weight of an object,W =?

Mass,m = 100 kg

\rm W= mg \\\\ \rm W= 100  \ kg  \times 9.81 \ m/sec^2 \\\\ W=981 \ N

Hence the weight of an object willl be 981 N.

To learn more about the weight refer;

brainly.com/question/10069252

#SPJ1

6 0
1 year ago
A 0.90- kg mass attached to a vertical spring of force constant 170 N/m oscillates with a maximum speed of 0.20 m/s . Find the f
Alex

Explanation:

Given that,

The mass of the object, m = 0.9 kg

Force constant, k = 170 N/m

Maximum speed of the object, v = 0.2 m/s

Solution,

(a) The angular frequency of the object is given by :

\omega=\sqrt{\dfrac{k}{m}}

\omega=\sqrt{\dfrac{170}{0.9}}

\omega=13.74\ rad/s

The time period is given by :

T=\dfrac{2\pi}{\omega}

T=\dfrac{2\pi}{13.74}

T = 0.45 seconds

(b) The maximum velocity of the object in shm is given by :

v=A\omega

Amplitude,

A=\dfrac{v}{\omega}

A=\dfrac{0.2}{13.74}

A = 0.0145 m

(c) The maximum acceleration of the object is given by :

a=\omega^2A

a=(13.74)^2\times 0.0145

a=2.73\ m/s^2

Therefore, this is the required solution.

3 0
3 years ago
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