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patriot [66]
3 years ago
13

Energy can transform between different types. For each of the following examples, identify two energy transformations and the ty

pes of energy involved in the transformations: Cannonball fired upward from a cannon Diver jumping from a spring board Squirrel jumping from a tree and landing on the net of a trampoline
Physics
1 answer:
Jet001 [13]3 years ago
7 0

1. Cannonball fired upward from a cannon

here in this cannon we can say kinetic energy is converted into potential energy of the cannon.

here this is because when cannon ball is shot with some speed its kinetic energy is converted into potential energy at the top point of its path

2. Diver jumping from a spring board

when diver is jumping on spring board then spring potential energy is converted into kinetic energy of the diver.

here when spring is compressed the energy in it is in the form of spring potential energy while at the other form it is converted into kinetic energy of the diver when he jump off.

3. Squirrel jumping from a tree and landing on the net of a trampoline.

When squirrel is jumping from tree and landing on the net trampoline the gravitational potential energy of the squirrel will transform into the kinetic energy of squirrel and then it is transformed into the potential energy of the net trampoline.

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You are driving your motorcycle in a circle of radius 75 m on wet pavement. what is the fastest you can go before you lose tract
stira [4]

On driving your motorcycle in a circle of radius 75 m on wet pavement, the fastest you can go before you lose traction, assuming the coefficient of static friction is 0.20 is 147m/s

Friction helps to maintain the slipping of the vehicle on the road hence lays a very important role.

Maximum velocity of a road with friction is given by the formula,

v = μRg

where, v is the maximum velocity

μ is the coefficient of static friction

R is the radius of the circle road

g is the acceleration due to gravity

Given,

μ = 0.20

R = 75m

g = 9.8m/s²

On substituting the given values in the above formula,

v = 0.20× 75 ×9.8

v = 147m/s

So, the Maximum velocity of the wet road is 147m/s.

Learn more about Velocity here, brainly.com/question/18084516

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3 0
2 years ago
A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long a
IrinaK [193]

The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

To find the answer, we need to know about the time of flight and range of projectile motion.

<h3>What's the expression of range of a projectile motion?</h3>
  • Range = U²× sin(2θ)/g
  • U= initial velocity, θ= angle of projectile and g= acceleration due to gravity
  • U=√{Range×g/sin(2θ)}
  • Here, range= 2.20m, = 36.5°
  • U= √{2.20×9.8/sin(73)}

U= √{2.20×9.8/sin(73)} = 22.5m/s

<h3>What's the expression of time of flight in projectile motion?</h3>
  • Time of flight= (2×U×sinθ)/g
  • So, T= (2×22.5×sin36.5°)/9.8

= 2.73 s

Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

Learn more about the range and time period of projectile motion here:

brainly.com/question/24136952

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4 0
2 years ago
A car has an engine which delivers a constant power. It accelerates from rest at time t = 0, and at t = t0 its acceleration is a
olga2289 [7]
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.
</span>
7 0
3 years ago
During a test, a solution placed on a sheet
suter [353]

Answer:

B. Acidic

Explanation:

Neutral an Basic solutions wouldn't create any reaction

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Which of the following diagrams shows the path of deep water currents in the ocean?
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I hope this helps. ^-^

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