Answer:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. The total momentum of the trolleys after separation is zero
c. The momentum of the 2 kg trolley after separation is 12 kg·m/s
d. The momentum of the 3 kg trolley is -12 kg·m/s
e. The velocity of the 3 kg trolley = -4 m/s
Explanation:
a. The total momentum of the trolleys which are at rest before the separation is zero
b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0
c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s
d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s
e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley
∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s
The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s
Answer:
The color of the central maximum is white.
Explanation:
A diffraction grating in optics is generally known as an optical component that contains a periodic structure. It is commonly used to breakdown and diffract light into different beams that move in several directions. For example, if a light ray is allowed to pass through the component (i.e. diffraction grating), the central maximum will have a white color.
The weight of an object mass of 100 kg on the surface of a Planet willl is 981 N.
<h3>What is weight?</h3>
The weight of matter is found as the product of the mass and the gravitational acceleration;
Given data;
Weight of an object,W =?
Mass,m = 100 kg

Hence the weight of an object willl be 981 N.
To learn more about the weight refer;
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Explanation:
Given that,
The mass of the object, m = 0.9 kg
Force constant, k = 170 N/m
Maximum speed of the object, v = 0.2 m/s
Solution,
(a) The angular frequency of the object is given by :



The time period is given by :


T = 0.45 seconds
(b) The maximum velocity of the object in shm is given by :

Amplitude,


A = 0.0145 m
(c) The maximum acceleration of the object is given by :



Therefore, this is the required solution.