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geniusboy [140]
3 years ago
14

A buffer is prepared by mixing 204.0 mL of 0.452 mol/L hydrochloric acid (HCI) and 500.0 mL of 0.400 mol/L sodium acetate (NaCHC

O2, NaAc). What is the pH of the above buffer solution?
Chemistry
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

pH of buffer is 4.81

Explanation:

The reaction between HCl and sodium acetate will product acetic acid. The presence of weak acid (acetic acid) and its salt will make a buffer.

The reaction will be:

CH_{3}COONa + HCl --> CH_{3}COOH + NaCl

Thus one mole each of HCl and acetate will give one mole of acetic acid.

The moles of HCl present = molarity X volume = 0.452 X 0.204 =0.092

moles of acetic acid formed on reaction of HCl with acetate = 0.092

Initial moles of sodium acetate present = molarity X volume = 0.4X0.5 =0.2

moles of sodium acetate left =0.108 mol

the pKa of acetic acid =4.74

The pH of buffer is calculated using Henderson Hassalbalch's equation :

pH = pKa + log\frac{[salt]}{[acid]}

pH = 4.74 +log\frac{0.108}{0.092} =4.81

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Question 23
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Answer:

Option B. 0.136 g

Explanation:

The balanced equation for the reaction is given below:

2AgNO3(aq) + 2NaOH(aq) —> Ag2O(s) + 2NaNO3(aq) + H2O(l)

Next, we shall determine the masses of AgNO3 and NaOH that reacted and the mass of Ag2O produced from the balanced equation. This is illustrated below:

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Mass of AgNO3 from the balanced equation = 2 x 170 = 340g

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Molar mass of Ag2O = (108x2) + 16 = 232g/mol

Mass of Ag2O from the balanced equation = 1 x 232 = 232g

Summary:

From the balanced equation above,

340g of AgNO3 reacted with 80g of NaOH to produce 232g of Ag2O.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

340g of AgNO3 reacted with 80g of NaOH.

Therefore, 0.2g of AgNO3 will react with = (0.2 x 80)/340 = 0.047g of NaOH.

From the calculations made above, only 0.047g out of 0.2g of NaOH given, reacted completely with 0.2g of AgNO3. Therefore, AgNO3 is the limiting reactant and NaOH is the excess reactant.

Now, we can calculate the mass of Ag2O produced from the reaction of 0.2g of AgNO3 and 0.2g of NaOH.

In this case, we shall use the limiting reactant because it will produce the maximum yield of Ag2O as all of it is used up in the reaction.

The limi reactant is AgNO3 and the mass of Ag2O produced can be obtained as follow:

From the balanced equation above,

340g of AgNO3 reacted to produce 232g of Ag2O.

Therefore, 0.2g of AgNO3 will react to produce = (0.2 x 232)/340 = 0.136g of Ag2O.

Therefore, 0.136g of Ag2O was produced from the reaction.

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