Answer:
As2O3 → H3AsO4
As2O3 → 2H3AsO4 balance As
5H2O + As2O3 → 2H3AsO4 balance O by adding H2O to one side
5H2O + As2O3 → 2H3AsO4 + 4H+ balance H by adding H+ to one side
5H2O + As2O3 → 2H3AsO4 + 4 H+ + 4e- balance charge by adding electrons to one side
Now do the same for the other part of the reaction
NO3- → NO
NO3- → NO + 2H2O
4H+ + NO3- → NO + 2H2O
3e- + 4H+ + NO3- → NO + 2H2O
Now cancel the electrons by multiplying the first equation by 3 and the second equation by 4, then add them together
.
3As2O3 + 4NO3- + 7H2O + 4H+ → 6H3AsO4 + 4NO
Answer:
Benzene: 37.5 Torr
Methylbenzene: 12.5 Torr
Explanation:
By Raoult's Law, each substance in a gas mixture contributes to the total pressure of the mixture proportionally to their respective mole fraction. So,
Ppartial = x*P°
Where x is the mole fraction (0.5 for each one because it's equimolar), and P° is the vapor pressure.
Benzene: Ppartial = 0.5 * 75 = 37.5 Torr
Methylbenzene: Ppartial = 0.5 * 25 = 12.5 Torr
Answer:
4 significant figures
Explanation:
Significant figures are the units/digits within a number that make the number more accurate and precise.
All digits (except for 0) are always significant. Therefore, all the digits in 43.55 are significant. Since there are 4 digits in the given number, there are 4 significant figures.
0.0760 m
do this by:
finding the moles of NaOH which will be <span>5.702 E -3 m
</span>
next find the moles of H3PO4 which will be <span>1.90 E -3 m</span><span>
calulcate </span>25 ml sample molarity = 0.07603 m, just put 0.0760<span>
</span>
Answer:
Q = 1461.6 J
Explanation:
Given data:
Mass of ice = 36 g
Initial temperature = -20°C
Final temperature = 0°C
Amount of heat absorbed = ?
Solution:
specific heat capacity of ice is 2.03 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 0°C - (-20°C)
ΔT = 20°C
Q = 36 g ×2.03 j/g.°C×20°C
Q = 1461.6 J
