2.8 billion miles which can be said as 4.5 billion kilometres
hope this helps x
Answer:
given an element U of relative atomic mass 10.8 for example with isotopes U-10 and U-11 we can get their percentages by the following steps.
Explanation:
1:let the Percentage of U-10 equal to X% and percentage of U-11equal to Y%.
2:The addition of X% and Y% equal to 100%.
3:X%=100%-Y%
4:X% of U-10 +Y% of U-11=10.8
5: substitute 3 in 4.
6: i.e (100-Y)% of U-10+Y% of U-11=10.8.
7:(100-Y)/100 of 10 +Y/100 of 11=10.8.
8:100-Y/10 +11Y=10.8.
9:(1000-10Y+11Y)/100=10.8.
10:1000+Y=10.8*100
11:1000+Y=1080.
12:Y=1080-1000.
13:Y=80.
14: from 3,X=100%-Y%.
X=100%-80%=20%.
15: Therefore, the percentage of isotopes in the isotopic mixture are 20% U-10 and 80% U-11.
E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
a) M(N</span>₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, <span>CO and N</span>₂ <span>have iexact molecular masses and will effuse at nearly identical rates.</span>
Answer:
smelling it without glasses or putting your face/nose really close to the substance
Explanation:
Hydrogen react with with carbon monoxide(Carbon (ii) oxide) to form methyl alcohol
CO + 2H2 ----> CH3OH
step one calculate the number of moles of H2
= 11g/2.0 g/mol (molar mass of H2 moles = 5.5moles
calculate the moles CO = 37.25grams/28 =1.330moles
The reacting ratio of of H2 to CH3OH 2:1
1.330 x 2/1+2.661 moles of H2 but there is more H2 present than that of co
therefore the grams of CH3OH is threfore =1.330 x32(molar mass of CH3OH) =42.65grams