Answer:
molarity = 0.385 moles/kg
Explanation:
Assume that the volume of the aqueous solution given is 1 liter = 1000 ml
Now, density can be calculated using the following rule:
density = mass / volume
Therefore:
mass = density * volume = 1.23 * 1000 = 1230 grams
Now, 0.467 m/L * 1L = 0.467 moles of HCl
We will get the mass of the 0.467 moles of HCl as follows:
mass = molar mass * number of moles = (1+35.5)*0.467 = 17.0455 grams
Now, we have the mass of the solution (water + HCl) calculated as 1230 grams and the mass of the HCl calculated as 17.0455 grams. We can use this information to get the mass of water as follows:
mass of water = 1230 - 17.0455 = 1212.9545 grams
Finally, we will get the molarity as follows:
molarity = number of moles of solute / kg of solution
molarity = (0.467) / (1212.9594*10^-3)
molarity = 0.385 mole/kg
Hope this helps :)
Answer:
C. Atoms of elements with five to seven valence electrons form anions in order to meet the octet rule.
Explanation:
- Atoms of elements gain or lose electron(s) to obey the octet rule by forming cations or anions.
- Atoms with 1 to 3 valence electrons lose electrons to form cations in order to attain a stable configuration.
- Atoms with 5 to 7 valence electrons gain electron(s) to form anions in order to attain stable configuration.
- However, atoms with 8 valence electrons do not require to gain or lose electrons since they an octet configuration.
- Atoms of metallic elements such as those in group 1 and 2 lose electron(s) to form cations while atoms of non-metallic elements such as halogens require to gain electron(s) to form anions so as to obey the octet rule.
The ability of a liquid to flow up a narrow tube which is unassisted against the gravity of the attraction between molecules of the same substance. The curvature which is of the surface of a liquid at the interface with the container, the attraction between dissimilar molecules for the resistance of a liquid to flow the elasticity of surface layer of liquid because of the liquid trying to minimize its surface area.
It will always produce a near-exact measurement
