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WITCHER [35]
2 years ago
15

If you need 2.5 moles of Rb2Cr7, how many grams do you need?

Chemistry
1 answer:
BartSMP [9]2 years ago
5 0

Answer:

0

Explanation:

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True or false: when a catalyst is added to a chemical reaction the particles collide with more energy
Stella [2.4K]

Answer:true

Explanation:

4 0
3 years ago
Which shell are the valence electrons of a germanium atom in the ground state located
yKpoI14uk [10]
It would be in the fourth shell.
7 0
3 years ago
a sample of solid is decomposed and found to contain 6.52g of potassium, 4.34 g of chromium and 5.34 of oxygen, what is the empi
Fynjy0 [20]

Answer:

K₂CrO₅

Explanation:

The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:

Elements                         Potassium                 Chromium         Oxygen

Mass                                  6.52                             4.34                  5.34

Molar mass                          39                               60                      16

Number of moles             6.52/39                     4.34/60             5.34/16

                                             0.167                          0.072              0.333

Divide through by

the smallest                      0.167/0.072             0.072/0.072          0.333/0.072

                                            2.3                               1                                4.6

                                             2                                 1                                  5

Empirical formula K₂CrO₅

5 0
3 years ago
Although I am solid, I am so light that I can float in any liquid listed on the chart. What am I?-----
evablogger [386]

Answer:

I know that Aerogel is the lightest metal in existence, but I don't think it would help much with your answer. I mean you can give it a try?

3 0
3 years ago
A patient receives 3.3 L of glucose solution intravenously (IV). If 100. mL of the solution
artcher [175]

Answer:

660kcal

Explanation:

The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.  

We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:  

3.3L * (1000mL / L) * (5g/100mL)= 165 g.

If glucose will give 4kcal/ g, then the total calories 165g glucose give will be: 165g * 4kcal/ g= 660kcal.

6 0
3 years ago
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