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lakkis [162]
4 years ago
7

What is the average salinity of ocean water

Chemistry
2 answers:
pentagon [3]4 years ago
5 0
3.45g/kg 
Hope I helped!
Georgia [21]4 years ago
5 0

its 34.5 i took the test

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A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.
Alenkinab [10]

Answer:

\Delta V = 234.736\,mL

Explanation:

The quantity of moles of ethanol in the solution is:

n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)

n_{C_{2}H_{5}OH} = 4.985\,mol

The mass and volume of ethanol in the solution are, respectively:

m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)

m_{C_{2}H_{5}OH} = 229.658\,g

V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }

V_{C_{2}H_{5}OH} = 290.964\,mL

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)

\Delta V = 234.736\,mL

8 0
3 years ago
39. suppose an aqueous solution contains both table sugar and table salt. can you separate either of these solutes from the wate
Degger [83]

Answer:

No, assuming that the salt/sugar is already dissolved

Explanation:

As long as the particle size is too big, it won't filter through. Therefore, if it is dissolved, it will pass through the filter.

If you were to throw rocks in there or something, and they are non-dissolvable, then yes.

7 0
2 years ago
Oxycodone (C18H21NO4), a narcotic analgesic, is a weak base with pKb = 5.47. Calculate the pH of a .00500 M oxycodone solution.
Ganezh [65]

Answer:

pH = 10.11

Explanation:

Hello there!

In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:

C_{18}H_{21}NO_4+H_2O\rightleftharpoons C_{18}H_{21}NO_4H^+OH^-

We can therefore set up the corresponding equilibrium expression:

Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}

Which can be written in terms of the reaction extent, x:

Kb=\frac{x^2}{0.00500M-x}=3.39x10^{-6}

Thus, by solving for x we obtain:

x_1=-0.000132M\\\\x_2=0.0001285M

However, since negative solutions are now allowed, we infer the correct x is 0.0001285 M; thus, the pOH can be computed:

pOH=-log(x)=-log(0.0001285)=3.89

And finally the pH:

pH=14-pOH=14-3.89\\\\pH=10.11

Best regards!

5 0
3 years ago
What is stoichiometry used for
Dennis_Churaev [7]

Answer:

Stoichiometry measures these quantitative relationships, and is used to determine the amount of products and reactants that are produced or needed in a given reaction.

3 0
4 years ago
Read 2 more answers
The picture is above^ someone help me please :)
Ronch [10]

Answer:

idk plz do not report

Explanation:

8 0
4 years ago
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