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kap26 [50]
3 years ago
9

An automobile travels on a straight road at 30 km/h How long will it take to travel 40 km

Physics
1 answer:
Anna [14]3 years ago
4 0

Answer:

the time taken for the automobile to travel the given distance is 80 mins.

Explanation:

Given;

speed of the automobile, v = 30 km/h

distance traveled by the automobile, x = 40 km

The time taken for the automobile to cover the given distance is calculated as;

time = distance / speed

time = 40 / 30

time = 1.3333 hours = 1.3333 hr x 60mins/hr = 80 mins

Therefore, the time taken for the automobile to travel the given distance is 80 mins.

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A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a
VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

r_1 = 45 sin15 \hat i + 45 cos15 \hat j

r_1 = 11.64 \hat i + 43.46\hat j

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

r_2 = 30 cos15\hat i + 30 sin15 \hat j

r_2 = 28.98\hat i + 7.76 \hat j

now the displacement of the boat is given as

d = r_2 - r_1

d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)

d = 17.34 \hat i - 35.7 \hat j

so the magnitude is given as

d = \sqrt{17.34^2 + 35.7^2}

d = 39.7 km

4 0
3 years ago
Light hits a clear plastic bottle and a granite rock. Which choice most accurately describes the effect of visible light on the
balu736 [363]

Answer:

#4 is the accurate answer.

8 0
4 years ago
Read 2 more answers
A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at
natka813 [3]
First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.

To solve this, you will want to create a proportion.

Flagpole height/flagpole shadow=building height/building shadow

Therefore, it should look like this:
50/30= 300/x

Solve for x:
50x=9,000
X= 180 feet

YOUR ANSWER IS C.
7 0
3 years ago
The crisis in Erikson’s identity versus role confusion stage of psychosocial development is that the individual must __________.
sergeinik [125]

C. realize who or what one wants to be

8 0
3 years ago
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Monochromatic light falls on a slit that is 2.30×10−3mm wide. Part A If the angle between the first dark fringes on either side
slava [35]

Answer:

Wavelength, \lambda=1.28\times 10^{-6}\ m

Explanation:

Given that,

Width of the slit, d=2.3\times 10^{-3}\ mm=2.3\times 10^{-6}\ m

The angle between the first dark fringes on either side of the central maximum is 34 degrees

To find,

The wavelength of the light used.

Solution,

The equation of maxima is given by :

dsin\theta=n\lambda

n = 1 here

\lambda=\dfrac{d\ sin\theta}{n}

\lambda={d\ sin\theta}

\lambda={2.3\times 10^{-6}\times sin(34)}

\lambda=1.28\times 10^{-6}\ m

So, the wavelength of the light used is 1.28\times 10^{-6}\ m. Hence, this is the required solution.

5 0
3 years ago
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