Answer:
Final temperature = 1279.25 K
Explanation:
We can solve this using the formula for Charles law since we are given volume and temperature.
From Charles law, we know that;
V1/T1 = V2/T2
Where;
T1 is the initial temperature
V1 is the initial volume
T2 is the final temperature
V2 is the final volume
We are given;
V1 = 2 L
T1 = 301 K
V2 = 8.5 L
Thus, making T2 the subject, we have;
T2 = V2•T1/V1
Plugging in the relevant values;
T2 = 8.5 × 301/2
T2 = 1279.25 K
Answer:
Q = 30284.88 j
Explanation:
Given data:
Mass of ethanol = 257 g
Cp = 2.4 j/g.°C
Chnage in temperature = ΔT = 49.1°C
Heat required = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = 257 g× 2.4 j/g.°C × 49.1 °C
Q = 30284.88 j
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