1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nastasia [14]
3 years ago
7

g 3. Doppler Shift (easy). As you sit out on the grass enjoying a sunny day, someone else in the park is flying a very annoying

drone that is emitting sound at 600 Hz. The drone flies over head with a velocity of 30 m/s. What frequency do you hear as the drone approaches? What frequency do you hear after it has passed and is moving away from you?
Physics
1 answer:
Masja [62]3 years ago
8 0

Answer:

Frequency when drone approaches = 657.50 Hz (Approx)

Frequency when drone passed = 551.74 Hz (Approx)

Explanation:

Given:

Frequency = 600 Hz

Velocity before (v₁) = 30 m/s

Velocity after (v₂) = -30 m/s

Find:

Frequency when drone approaches = ?

Frequency when drone passed = ?

Computation:

We, know that speed of sound (V) = 343 m/s

Frequency when drone approaches = [V/(V-v₁)]Frequency

Frequency when drone approaches = [343/(343-30)]600

Frequency when drone approaches = [343/(313)]600

Frequency when drone approaches = 657.50 Hz (Approx)

Frequency when drone passed = [V/(V-v₂)]Frequency

Frequency when drone passed = [343/(343-(-30))]600

Frequency when drone passed = 551.74 Hz (Approx)

You might be interested in
If the normal force exerted by the track on the car when it is at the top of the track (point B) is 6.00 N , what is the normal
Eddi Din [679]

Answer:

So, the force, F is the agent which provides the basic property of motion or rest to the body.While, the car is more obviously to have a mass, m and that the angle withe road or surface is also given which is normal to the road(i.e angle =90 degree). Then we say that lets say that the car is moving with the constant velocity of 20 m/sec and its kept unchanged by the car. So, we have the mass, m as 1 kg for the car and the value of the gravity we have the g=9.8 m/sec.

Now,

We have F=ma,

and a=v/t,

so we can have another equation for it as,

Now, providing the required data  to, it;  ∴t =2 sec,

F=(1)×(20/2),

  • <u>F=10 N.</u>
  • So, the car would be acting the force,F of about 10 N  while the car is present on the lower region of the track.

4 0
3 years ago
A body is at aheight of 81m and is ascending upwards with a velocity of 12m/s .a body of 2 kg weight is dropped from it.if g=10m
butalik [34]
First the velocity drops to zero in 1.2 secs. In those seconds it went upwards for 7.2 m, then it went from 87.2 to 0m. x-x0=v0*t+1/2*g*t^2 ergo t=sqrt(2x/g) that is 4.1761 s. Finally the total time required is 5.3761 s
7 0
3 years ago
Coal is a major fossil fuel which is mined in many countries around the world. Which of these is most likely to happen if coal i
Troyanec [42]
<span>If coal is stacked near mines, the most likley thing that will happen is that rain watter will carry contaminants in coal into durface water. When rain falls on coal, it erodes it just like any other rock. So amounts of coal can be washed out of its holding area and into surface *and* groundwater. Correct answer:D</span>
6 0
3 years ago
Two girls,(masses m1 and m2) are on roller skates and stand at rest, close to each other and face-to-face. Girl 1 pushes squarel
Arturiano [62]

Answer:

\vec{v}_1 = -\frac{\vec{v}_2m_2}{m_1}

Explanation:

The center of mass of the system (two girls) is constant, as the velocity of the center of mass of the system is also constant.

\vec{v}_{cm} = \frac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}

<u>The initial velocity of the system is zero, since both girls are at rest.</u> So the velocity of the total system at any point should be zero as well.

0 = \frac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}\\\vec{v}_1 = -\frac{\vec{v}_2m_2}{m_1}

This is true, because there is no friction between the girls and the ground. Otherwise, the velocity of the center of mass wouldn't be constant.

5 0
3 years ago
Question 5 (1 point)
Sophie [7]

Main answer- the velocity of 2.2kg ball is 12.566m/s

supporting answer-   In circular motion the velocity is termed as angular velocity

Angular velocity represents the rate of variation of an object's position angle with respect to time.

W =theta/ time

W = length of the arc/ radius of circle × time

body of the answer-2πr/r×t =2π/t

2×π/ 0.5 = 12.566 m/s

final answer- hence the velocity of ball is revolving is 12.566 m/s

to learn more about velocity of a rotating object  link

https://brainly.in/question/46395358

#SPJ1

3 0
1 year ago
Other questions:
  • Colorful light emissions are applicable to everyday life. where else have you observed colorful light emissions? are these light
    6·1 answer
  • What happens to water when it changes to ice?
    12·2 answers
  • Why does earth orbit the sun instead of the moon? A) the sun is larger than the moon B) The sun is brighter than the moon C) The
    8·2 answers
  • Two police cars have identical sirens that produce sound of frequency of 570 Hz. A stationary listener is standing between two c
    15·1 answer
  • Calculate the change in entropy when 1.00 kg of water at 100 degree C is vaporized and converted to steam at 100 degree C. Assum
    15·1 answer
  • Part 1. Define the following terminologies
    9·1 answer
  • Work is done when : 11 point)
    7·1 answer
  • When energy and matter are paired with what they are one in the same
    5·1 answer
  • A 3.0-kg ball with an initial velocity of (4.0i + 3.0j) m/s collides with a wall and rebounds with a
    11·1 answer
  • A situation for effect of force leads to a permanent change in shape of object is.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!