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3 years ago

How do I put a starter in my Chevy 350

Engineering

1 answer:

lbvjy [14]3 years ago

3 0

Add a carborator and a battery and this should be a start....?

Explanation:needa little gas and electricity to jave and ignition to turn moto by a starter...i think

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Argon is compressed in a polytropic process with n=1.2 from 120 kPa and 10 °C to 800 kPa in a piston cylinder device. Determine:

Jlenok [28]

Answer:

a. W = - 108.89 kJ/kg

b. q = - 75.846 kJ/kg

Given:

n = 1.2

Pressure, P = 120 kPa

Temperature, T = $10^{\circ}$ = 283 K

Pressure, P' = 800 kPa

Solution:

(a) Work Produced:

Now, using the relation:

W = $\frac{RT}{1 - n}[(\frac{P'}{P})^(1 - \frac{1}{n}) - 1]$

where

R = Rydberg's constant

Now,

W = $\frac{283\times0.208}{1 - 1.2}[(\frac{800}{120})^(1 - \frac{1}{1.2}) - 1]$

W = $\frac{283\times0.208}{- 0.2}[(6.67)^(0.16) - 1] = - 108.89 kJ/kg$

Now,

$\frac{T'}{T}= (\frac{P'}{P})^{1 - \frac{1}{n}}$

$T'= T(\frac{800}{120})^{1 - \frac{1}{1.2}}$

$T'= 1.37\times 283 = 388.48 K$

(b) Heat tranferred, q = $C_{v}(T' - T) + W$

q = $0.3122(388.84 - 283) - 108.89 = - 75.846 kJ/kg$

5 0

3 years ago

In a four bar mechanism, L, is a fixed link; L2 is driver crank; L3 is coupler and L4 is follower crank. L=27 cm, L3 =5 cm and L

Lera25 [3.4K]

Answer:

$L_1>32 cm$

Explanation:

Given that

$L_2=27 cm$

$L_3=5 cm$

$L_4=10 cm$

Here shortest link is link3

To make the linkage as a double rocker mechanism we have to fix longest link that link is link1

So for double rocker mechanism

$L_3+L_1>L_2+L_4$

Now put the values

$5+L_1>27+10$

$L_1>32 cm$

It means that length of link1 should be greater than 32 cm.

6 0

3 years ago

A 50 mol% mixture of propane (1) and n-butane (2) enters an isothermal flash drum at 37°C. If the flash drum is maintained at 0.

Ulleksa [173]

Answer:

Explanation:

given data :

xi=0.5 (i.e. mole fraction 50%)

two liquid mixtures are given i.e. propane and n-butane

generally raoults law is applicable to ideal mixtures

the basic equation of raoults law

ki=pi saturated (T)/p...............1

first we take propane liquid

the basic forula to calculate psat is

%log psat=A-B/T(K)+C

for this we need to calculate tv=B-C/A-ln(P)

Substitute the values from antoine data

B=803.997,A=3.92828,C=26.11,P=0.6*10^-3

TV= 44.74K

NOW WE WILL take n-butane and calculate tv

for butane antoine data is as follows

B=2292,A=13.98,C=-27.86

Tv=134.96 k

now calculating psat

%log psat=A-B/T(K)+C

Psat for propane is -11.29 bar

psat for n-butane is -21.27 bar

pure component of vapour pressure is

1. p1=xi*psat=0.5*-11.29=-5.645 bar

2.p2=xi*psat=0.5*-21.27=-10.635 bar

2. now we are calculating the composition of phase

to calculate the composition

first we need to add up all the pure component pressure

p=p1+p2=-5.645+10.635=4.99 bar

i am assuming yi as vapour composition

yi=p1/p=-5.645/4.99=-1.131

y2=p2/p=-10.635/4.99=-2.131

so these are the minimum values of vapour pressure and pure component vapour pressure

4 0

3 years ago

Which engineers are requried to have a PE (professional engineer) license?

Elena-2011 [213]

Professional engineers need to complete a four year college degree, work under a Professional Engineer for four years, pass two intensive competency exams, and earn a license from their state’s licensure board.

7 0

2 years ago

Read 2 more answers

Please help me on this it’s due now

lbvjy [14]

Answer:

road closures on deliver routes.. i think..

5 0

2 years ago